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3 years ago

Which of the following is a description of a greatest common factor.

Mathematics

1 answer:

Simora [160]3 years ago

3 0

Don’t open the link it’s a hacking business Good luck.

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Carissa also has a sink that is shaped like a half sphere. The sink has a volume of 4000/ 3 * π in 3. One day, her sink clogged.

givi [52]

Answer:

Part a) 119 cups

Part b) 30 cups

Step-by-step explanation:

Part a)

step 1

Find the volume of the conical cup with a diameter of 4 in. and a height of 8 in

The volume of the cone (cup) is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=4/2=2\ in$ ----> the radius is half the diameter

$h=8\ in$

assume

$\pi =3.14$

substitute

$V=\frac{1}{3}(3.14)(2^{2})8=33.49\ in^3$

step 2

Find out how many cups of water must Carissa scoop out of the sink

Divide the volume of the sink by the volume of the cup

$\frac{4,000}{33.49}= 119\ cups$

Part b)

step 1

Find the volume of the conical cup with a diameter of 8 in. and a height of 8 in

The volume of the cone (cup) is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=8/2=4\ in$ ----> the radius is half the diameter

$h=8\ in$

assume

$\pi =3.14$

substitute

$V=\frac{1}{3}(3.14)(4^{2})8=133.97\ in^3$

step 2

Find out how many cups of water must Carissa scoop out of the sink

Divide the volume of the sink by the volume of the cup

$\frac{4,000}{133.97}= 30\ cups$

7 0

3 years ago

❗️HELP❗️ I need help with part a,b, and c. Idk if I got part a and b correct pls help me! Thank you

finlep [7]

U want me to help u with all

3 0

4 years ago

5. given ABC, find the value of x

Fudgin [204]

There's no question g

6 0

3 years ago

How do I delete my questions?

pishuonlain [190]

Email them ..they will help you

https://blog.brainly.in/contact/

3 0

3 years ago

Determine which equation is parallel to the line JK and which is perpendicular to like JK

sattari [20]

Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and $y = - \frac{1}{m}x + b$ will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as

y = mx + c ............. (1)

Therefore, the equation has slope = m

Now, any straight line having an equation with slope m will be parallel to line JK.

So, the equation of the straight line which is parallel to equation (1) will be

y = mx + c', where, c' is any real constant.

Now, let us assume that another straight line having equation

y = nx + a is perpendicular to the line JK i.e. equation (1).

Now, we know if two lines are perpendicular to each other then the product of their slopes will be - 1.

So, mn = - 1

⇒ $n = - \frac{1}{m}$

Therefore, the equation of a straight line which is perpendicular to equation (1) will be $y = - \frac{1}{m}x + b$ where b is any real constant. (Answer)

3 0

3 years ago

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