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Galina-37 [17]
2 years ago
10

What is 3 divided by 1107 please show work will give brainliest! (:

Mathematics
2 answers:
Lilit [14]2 years ago
8 0

Answer:

0.0027100271

3/1107=0.0027100271

GrogVix [38]2 years ago
4 0
  1. 3 \div 1107 = 369
  2. i dont know how to show my solution
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Find the area of a square if its sides measure 2 2/3m
olga55 [171]

Answer:

7\dfrac{1}{9}\ m^2

Step-by-step explanation:

If the length of the square side is a units, then the area of the square is

A=a^2\ un^2.

In your case, the side length is

a=2\dfrac{2}{3}\ m,

then the area is

A=2\dfrac{2}{3}\cdot 2\dfrac{2}{3}\\ \\ \\A=\dfrac{2\cdot 3+2}{3}\cdot \dfrac{2\cdot 3+2}{3}\\ \\ \\A=\dfrac{8}{3}\cdot \dfrac{8}{3}\\ \\ \\A=\dfrac{64}{9}\\ \\ \\A=7\dfrac{1}{9}\ m^2

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3 years ago
I need help!!!!!!!!!!!!!
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Answer:

The perimeter is 38 but it gets rounded to 40

Step-by-step explanation:

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2 years ago
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2 years ago
Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together the
klasskru [66]

The rate charged per hour by each mechanic was:  x = 75 $ / hr and y = 115 $ / hr.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given;

The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours.

Together they charged a total of $3225.

For this case we have the following variables:

x be the amount of $ / hr that the mechanic obtains 1.

y be the amount of $ / hr obtained by mechanic 2.

An equation to express this would be:

x + y = 190

20x + 15y = 3225

Solving the system of equations we have:

20x + 15(190 -x) = 3225

20x + 2850 - 15x = 3225

5x = 375

x = 75

simililary

y = 190 - x

y = 115

Hence, the rate charged per hour by each mechanic was:

x = 75 $ / hr

y = 115 $ / hr

Learn more about equations here;

brainly.com/question/10413253

#SPJ1

6 0
1 year ago
If f x equals x -3 + g x equals 1 - x 2 - 9 find ( f og) (x and give any restrictions on its domain
evablogger [386]
\begin{gathered} f(x)=x-3 \\ g(x)=\frac{1}{x^2-9} \\ (\text{fog)(x)}=\frac{1}{x^2-9}-3 \end{gathered}

the denominator cannot be zero, because the division by zero is not defined, therefore:

\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}

Therefore the domain of (f o g)(x) is:

D\colon(-\infty,-3)\cup(-3,3)\cup(3,\infty)

3 0
1 year ago
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