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Lapatulllka [165]
3 years ago
11

A​ student's cost for last semester at her community college was ​$2000. She spent ​$280 of that on books. What percent of last​

semester's college costs was spent on​ books?
Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

14%

Step-by-step explanation:

A way I usually do it is with a fraction setup.

280/2000 = ?/100

multiply 280 by 100, and you get 28000. divide this by 2000, and you get 14!

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3 years ago
(8y²)(-3x²y²)(2/3xy⁴)<br><br> HELP PLEASEEEEEEEE
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Step-by-step explanation:

1 Remove parentheses.

8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}

8y

2

×−3x

2

y

2

×

3

2

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2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

b

a

×

d

c

=

bd

ac

.

\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}

3

8y

2

×−3x

2

y

2

×2xy

4

3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(8×−3×2)y

2

y

2

y

4

x

2

x

4 Simplify 8\times -38×−3 to -24−24.

\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(−24×2)y

2

y

2

y

4

x

2

x

5 Simplify -24\times 2−24×2 to -48−48.

\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

−48y

2

y

2

y

4

x

2

x

6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}

3

−48y

2+2+4

x

2+1

7 Simplify 2+22+2 to 44.

\frac{-48{y}^{4+4}{x}^{2+1}}{3}

3

−48y

4+4

x

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8 Simplify 4+44+4 to 88.

\frac{-48{y}^{8}{x}^{2+1}}{3}

3

−48y

8

x

2+1

9 Simplify 2+12+1 to 33.

\frac{-48{y}^{8}{x}^{3}}{3}

3

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8

x

3

10 Move the negative sign to the left.

-\frac{48{y}^{8}{x}^{3}}{3}

−

3

48y

8

x

3

11 Simplify \frac{48{y}^{8}{x}^{3}}{3}

3

48y

8

x

3

to 16{y}^{8}{x}^{3}16y

8

x

3

.

-16{y}^{8}{x}^{3}

−16y

8

x

3

Done

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