9514 1404 393
Answer:
A) 5x+12 = -12x-12
D) 5x+12 = -5x-12
Step-by-step explanation:
If you subtract the right side expression from both sides, you will get an equation with something equal to zero. If the 'something' has a variable in it, there is exactly one solution.
A: (5x+12) -(-12x-12) = 17x+24 = 0 . . . one solution
B: (5x+12) -(5x-5) = 17 = 0 . . . . no solutions
C: (5x+12)-(5x+12) = 0 = 0 . . . . infinite solutions
D: (5x+12) -(-5x-12) = 10x +24 = 0 . . . one solution
Answer:
c
Step-by-step explanation:
The period is 1 complete cycle of the wave, before repeating.
1 cycle is from - 6 to - 2 , then
period = 4 → c
The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted 
, which we can parameterize by the vector-valued function,
for 
, which has differential
Then with 
, we have
Complete the square in the quadratic term of the integrand: 
, then in the integral we substitute 
:
Make another substitution of 
:
Integrate by parts, taking
So, we have by the fundamental theorem of calculus that
Answer:
A. x = 58°
B. x = 10m
C. a = 44°
All approximated to nearest whole number.
Step-by-step explanation:
All triangles given are right angled triangles. Therefore, we would apply the trigonometry functions to solve for each missing side and angle.
Recall: SOHCAHTOA
a. Adjacent = 4.8cm,
Hypotenuse = 9cm
Angle to find =x°
Thus, we would apply the following formula:
Cos θ = Adjacent/Hypotenuse
Cos θ = 4.8/9 = 0.5333
θ = Cos-¹(0.5333) = 57.77
x ≈ 58° (to nearest whole number)
b. Opposite side = x
Hypothenuse = 40 m
Included angle = 14°
We would use:
Sine θ = opposite/hypothenuse
Sin (14) = x/40
Multiply both sides by 40
40*sin(14) = x
40*0.2419 = x
x = 9.676 = 10 m (to nearest whole number)
c. Opposite = 87mm
Adjacent = 91mm
θ = a°
We would use:
Tan θ = opposite/adjacent
Tan θ = 87/91
Tan θ = 0.9560
θ = tan-¹(0.9560)
θ = a = 43.71
a ≈ 44° (to nearest whole number)
