Add and subtract fractions with negative signs. -4/5 + 6/5=?

Mathematics

2 answers:

Sergeu [11.5K]3 years ago

8 0

Answer:

0.4 or 2/5

Step-by-step explanation:

The fractions already have the same denominator so all that is left to do is add the numerators

-4+6=2

V125BC [204]3 years ago

4 0

Answer:

2/5

Step-by-step explanation:

when adding a positive to a negative, you can reverse the order so that you can remove the addition sign:

so instead of -4/5 + 6/5

you can make it 6/5 - 4/5 which equals 2/5 or .4

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aleksandrvk [35]

Answer: x = 2.65, y = 3.81

Step-by-step explanation:

ABC similar to PQR

1) Find the ratio of corresponding sides

2) Use that ratio to find values for x & y

1) Side AB = 2.76cm & Side PR = y cm

Side BC = x cm & Side RQ = 3.66 cm

Side CA = 3 cm & Side QP = 4.14 cm (both lengths given)

Can match 3 to 4.14 & ratio of sides in ABC to PQR= 3 /4.14

Length of sides ABC = 3/4.14 times the length of sides PQR

2) x = (3 / 4.14) * 3.66 = 2.65

Now solve for y, ABC to PQR: 2.76 = (3 / 4.14) (y )

equality property (both sides) & inverse operation to isolate y : . 2.76 ÷ (3 / 4.14) = (3 / 4.14 ) ÷ (3 / 4.14) (y)

2.76 * (4.14 / 3) = 3 / 4.14 * (4.14 / 3) (y)

(2.76 * 1.38 ) = 3.81 = y

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7 0

3 years ago

How can you tell from the equation of a rational function if the function has a hole in the graph ( a removable discontinuity) a

Eva8 [605]

Consider that,

x^2+4x+4 = (x+2)(x+2)

x^2+7x+10 = (x+2)(x+5)

Dividing those expressions leads to

(x^2+4x+4)/(x^2+7x+10) = (x+2)/(x+5)

The intermediate step that happened is that we have (x+2)(x+2) all over (x+2)(x+5), then we have a pair of (x+2) terms cancel as the diagram indicates (see below). This is where the removable discontinuity happens. Specifically when x = -2. Plugging x = -2 into (x+2)/(x+5) produces an output, but it doesn't do the same for the original ratio of quadratics. So we must remove x = -2 from the domain.