If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
no it's not because is not
Answer:
9m⁸
Step-by-step explanation:
3^2=9
(m⁴)² = m⁸
9*m⁸
Answer:
y< 5/6 - 7
Step-by-step explanation:
First, you have to send 5x to the other side so youĺl -5x and the equation will be -6y>-5x+42
Then, you divide the equation on the left side by -6 because youll want y by itself. Remember, when you divide by a negative, you flip the greater than/equal to sign. itll now be y<-5/6 - 7
done
In 5xy it would be 5x×1y and then 2y if they variable doesn't have a number infront of it it is assumed to be a One.
