Answer:
(-1, 4)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
10x + 6y = 14
-x - 6y = -23
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Add 2 equations together: 9x = -9
- Divide 9 on both sides: x = -1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: -x - 6y = -23
- Substitute in <em>x</em>: -(-1) - 6y = -23
- Multiply: 1 - 6y = -23
- Subtract 1 on both sides: -6y = -24
- Divide -6 on both sides: y = 4
Answer: 0 and 1, in that order
The numbers <u> 0 </u> and <u> 1 </u> are respectively the additive and multiplicative identities of rational numbers.
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Explanation:
The additive identity is 0 because adding 0 to any number leads to the original number. For instance, 7+0 = 7. In general we can say x+0 = x or we could also say 0+x = x.
The multiplicative identity is 1 because multiplying 1 with anything leads to that original number. Example: 1*5 = 5 or 9*1 = 1. The general template is x*1 = x which is the same as saying 1*x = x.
These ideas not only apply to rational numbers, but to real numbers as well.
Answer:
127
Step-by-step explanation:
400+1495=1895
1895/15=126.333333333
Answer:
=53*(54 ×^9 y^12 z^15)^1/2
=53*y^6 *z^(15/2) * x^( 9/2)* (54)^1/2