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lina2011 [118]
3 years ago
9

Solve for x. 5x - 6 = 4x + 8

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
8 0
<span>5x - 6 = 4x + 8
-4x        -4x

x - 6 = 8
    +6   +6

x = 14

Answer: x = 14</span>
Varvara68 [4.7K]3 years ago
4 0
First let's get X to one side by subtracting 4x from both sides. (5x-4x) -6 = 8. x-6=8. Now we add 6 to both sides to isolate "x". x=8+6=14. Our answer is x=14.
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If triangle ABC was rotated 90 degrees counterclockwise about the origin, what would the ordered pairs be for B'''?
Aliun [14]

Answer:

Point B is (-1,2)

Step-by-step explanation:

Given: A triangle ABC was rotated 90 degrees counterclockwise

To find: coordinates of the point B

Solution:

A triangle is three - dimensional figure that has three sides, three vertices and three angles.

Counterclockwise refers to the direction opposite to the direction of movement of hands of the clock.

As triangle ABC was rotated 90 degrees counterclockwise about the origin, point B is (-1,2)

3 0
3 years ago
6. Use synthetic substitution to evaluate the polynomial P(x) = x - 4x² + 4x – 5 for x = 4
Tatiana [17]

Answer:

When x=4

P(x) =4 - 4(4)^2 + 4(4) -5

=4 - 4(16) + 16 -5

=4 - 64 +11

= -60 + 11

= -49

8 0
3 years ago
Divide.<br>(10a^4-5a^3) / 5a
wolverine [178]
\boxed{\frac{10a^4-5a^3}{ 5a}=\frac{10a^4}{5a}-\frac{5a^3}{5a}=2a^3-a^2}
5 0
3 years ago
Answer question and show work please
SCORPION-xisa [38]
The recipes include: \frac{1}{2}\frac{3}{8}\frac{3}{10}
finding their lcm gives:
\frac{12,20,15}{40}
arranging them 
\frac{3}{10}\frac{3}{8}\frac{1}{2}
please mark as brainliest
5 0
3 years ago
F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
Read 2 more answers
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