Answer:
C. The height of a student and the day of the month a student was born.
Step-by-step explanation:
The day you were born does not have any effect on your height later in life. However, all of the other answers correlate with each other.
Answer:
When Amina is 18. Saad would be;
k. 14
Step-by-step explanation:
Let "x" represent Anita's current age and let "y" represent Saad's current age, we have;
Anita's age = 2 × Saad's age
Therefore;
x = 2 × y...(1)
In 4 years, we will get;
x + 4 = 1.5 × (y + 4)...(2)
Substituting the value of x in equation (1) into equation (2), we get;
2·y + 4 = 1.5·y + 1.5 × 4 = 1.5·y + 6
2·y + 4 = 1.5·y + 6
2·y - 1.5·y = 6 - 4 = 2
0.5·y = 2
y = 2/0.5 = 4
Saad's current age = y = 4 years
From equation (1), we have;
x = 2 × y = 2 × 4 = 8
Amina's current age = x = 8 years
When Amina is 18, we have;
18 = 10 + 8 = 10 + x
Therefore, Amina would be 18 in 10 years time from now, from which we have;
Saad would be 10 years + y = 10 years + 4 years = 14 years in 10 years from now
Therefore, when Amina would be 18 years in 10 years from now Saad would be 14 years.
Solving for the polynomial function of least degree with
integral coefficients whose zeros are -5, 3i
We have:
x = -5
Then x + 5 = 0
Therefore one of the factors of the polynomial function is
(x + 5)
Also, we have:
x = 3i
Which can be rewritten as:
x = Sqrt(-9)
Square both sides of the equation:
x^2 = -9
x^2 + 9 = 0
Therefore one of the factors of the polynomial function is (x^2
+ 9)
The polynomial function has factors: (x + 5)(x^2 + 9)
= x(x^2 + 9) + 5(x^2 + 9)
= x^3 + 9x + 5x^2 = 45
Therefore, x^3 + 5x^2 + 9x – 45 = 0
f(x) = x^3 + 5x^2 + 9x – 45
The polynomial function of least degree with integral coefficients
that has the given zeros, -5, 3i is f(x) = x^3 + 5x^2 + 9x – 45
Answer:
Step-by-step explanation:
Standard form for a circle is:
(h, k) is the center r is the radius
