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Setler [38]
3 years ago
10

20 minus 8 help .... 6×7. 2 differt questions answer separately

Mathematics
2 answers:
notka56 [123]3 years ago
6 0

20-8=12

6x7=42

i shall say this is correct

Iteru [2.4K]3 years ago
5 0

Answer:

43.2

Step-by-step explanation:

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Answer:

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Y intercept is where line touches y axis so x = 0.

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Solve for X and Y in the triangle shown below. Use the special right triangle rule to give exact answers.
natulia [17]

Answer:

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The part of the sphere x2 + y2 + z2 = 16 that lies above the cone z = x2 + y2 . (Enter your answer as a comma-separated list of
statuscvo [17]

Answer:

(x,y,z)=(ucos(v), usin(v), \sqrt{16-u^{2})

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Step-by-step explanation:

Equation of a cone is z=\sqrt{x^{2} +y^{2}}

Equation of a paraboloid is z=x^{2} +y^{2}

I have parametrised cone here. Please note that equation for cone in the question, is actually a paraboloid.

Imagine a sphere of radius 4, centered at origin and intersecting a cone also centered at origin and height along positive z-axis, given by the equations

x^{2} +y^{2} +z^{2} = 16\\z=\sqrt{x^{2} +y^{2}}

where z\geq x^{2} +y^{2}

Solving for these two equations, and substituting for z in the equation of sphere, we get a circle of radius 2\sqrt{2} units.

The equation of intersecting circle is:

x^{2} +y^{2}=8

Now, according to question, parametrizing this region of circle using parameters u and v.

Consider cylindrical co-ordinates: (r,θ,z)

In cylindrical co-ordinates

(x, y, z)= (r cos(θ),  r sin(θ), z)

x^{2} +y^{2}= r^{2}

Eliminating z, and changing (r, θ)=(u,v)

For cone: x=ucos(v)

y= usin(v)

z=\sqrt{16-u^{2}

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where 0\leq u\leq 2\sqrt{2} and 0\leq v\leq 2\pi

6 0
3 years ago
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