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Sergio039 [100]
3 years ago
6

Please help me with these questions.....please...

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0
The first one is A and the second one is B, hope this helps!!
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Divide 53 by 10. write the quotient as a mixed number
posledela

\frac{53}{10}  = 5 \frac{3}{10}

Hope this helps. - M
5 0
3 years ago
Which is equal to (2+3i)+(-4+i)?<br> A, -2-4i<br> B, -2-2i<br> C, -2+2i<br> D, -2+4i<br> E, 6+4i
inysia [295]

Answer:

D. -2+4i

Step-by-step explanation:

just combine like terms :)

6 0
3 years ago
Read 2 more answers
A cylindrical-shaped container requires 12 cubic feet of soil to be considered full. If a cone with a congruent base and height
stich3 [128]

The statement that describes the volumes of the two figures relate is: <em>The </em><em>volume of the cone</em><em> is 1/3 of the </em><em>volume of the cylinder</em>

Given the following:

Volume of cylindrical-shaped container = 12 cubic feet

Volume of cone-shaped container = 4 cubic feet

Ratio of the volume of the cone to the volume of the cylinder = 4 : 12 = 1 : 3

Therefore the statement that describes the volumes of the two figures relate is: <em>The </em><em>volume of the cone</em><em> is 1/3 of the </em><em>volume of the cylinder</em>

<em />

Learn more about the volume of cone on:

brainly.com/question/13677400

4 0
2 years ago
(1 point) The distribution of heights of adult men in the U.S. is approximately normal with mean 69 inches and standarddeviation
Ludmilka [50]

Part a)

The mean height is 69 inches with a standard deviation of 2.5 inches.

If we consider a interval of heights that relies on no more than two standard deviations from the mean, we will cover, approximatelly, 95% of men's heights. Then, we interval that we're looking for is:

Answer: 64 TO 74 INCHES

Part b)

Since [69,74] is half of the interval in the previous answer, we might expect half of 95% as the percentage of men who are in this interval. That is:

Answer: 47.5 PERCENT

Part c)

A interval of heights that relies on no more than one standard deviation from the mean covers, approximatelly, 68% of men's heights. Then, we can consider that the percentage of men that are between 64 and 66.5 inches is given by 47.5 - 68/2 = 13.5.

Answr: 13.5 PERCENT

3 0
1 year ago
By what percent (%) will a fraction change if its numerator is decreased by 10% and its denominator is decreased by 70%?
grandymaker [24]
Answer: 200% increase
7 0
3 years ago
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