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Oliga [24]
3 years ago
14

Hi can you help me in mate plissimplify the following algebraic expressions​

Mathematics
1 answer:
mixas84 [53]3 years ago
8 0

Answer:

3b

Step-by-step explanation:

\dfrac{24a^2b^4c^3}{8a^2b^3\sqrt[3]{c^9}} =

= 3a^{2 - 2}b^{4 - 3} \times \dfrac{c^3}{c^\frac{9}{3}}

= 3a^{0}b^{1} \times \dfrac{c^3}{c^3}

= 3bc^{3-3}

= 3bc^{0}

= 3b

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What is −5 1/2 ÷ (−4 1/2) ?/
RUDIKE [14]

Answer:

51÷41

Step-by-step explanation:

changing division form into multiplication by making its reciprocal

3 0
3 years ago
In the diagram of circle A, what is the measure of<br> ZXYZ?<br> 35°<br> 70°<br> 75°<br> 140°
postnew [5]

Using the intersecting secant theorem:

Angle xyz = 1/2( wz- XX)

Xyz = 1/2(175-105)

Xyz = 1/2(70)

Xyz= 35

The answer is 35 degrees

4 0
4 years ago
HELP ME WHATS THE VALUE OF X?
Y_Kistochka [10]

Answer:

Step-by-step explanation:

Total sum of degrees of a Triangle is 180 deg

Than: 8x-7 + x +7 + 2x + 15 = 180

11x + 15 = 180

x = (180-15) / 11  =15

Answer: 15

8 0
3 years ago
There are cars, trucks, and motorcycles in our company parking lot. The ratio of cars to trucks to motorcycles is $4:3:2.$ If th
Keith_Richards [23]

Answer:

12

Step-by-step explanation:

The ratio of cars to trucks to motorcycles is $4:3:2.

If there are $42$ cars and trucks total,

To get how many motorcycles are there

Sum up the ratio of cars and trucks 4:3= 4+3 = 7

Sum up the ratio of cars and trucks and motorcycles

4+3+2 =9

Let the total number of cars and trucks and motorcycles be represented as A

The total number of cars and trucks in the question is 42

(7/9) x A = 42

7A/9 = 42

cross multiply

7A = 42×9 = 378

A= 378/7 = 54

The total number of cars and trucks and motorcycles is 54

To get the number of motorcycles can be calculated through

a. The total number of cars and trucks and motorcycles subtracted by the number of cars and trucks = 54-42=12 or use the ratio which is

2/9 × 54 = 2×6=12

5 0
3 years ago
What is m/jsm? (Show Work)
Pie

m<SMJ + m<SME = 180° <em>(Linear pair) ⇒ </em>m<SMJ + 59° = 180°  ⇒ m<SMJ = 121°

m<MJS ≅ m<EJA: <E + <A + <J = 180° ⇒ 90° + 48° + <J = 180°  ⇒ <J = 42°

<u>m<JSM + m<SMJ + m<MJS = 180°  </u><u><em> (Triangle sum) </em></u>

m<JSM  + 121° + 42° = 180°

m<JSM  + 163° = 180°

m<JSM  = 17°

Answer: 17°

6 0
3 years ago
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