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Alexxandr [17]
3 years ago
13

If u understand help me out

Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

???

Step-by-step explanation:

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Is this correct way to solve the problem?
Shkiper50 [21]

Answer:

10x=40

x=40/10

x=4

4 is the answers, not -4

Step-by-step explanation:

pls mark as brainliest

8 0
3 years ago
6m + 3z + 4m + 2w - 5z
Snowcat [4.5K]

Step-by-step explanation:

6m + 3z + 4m + 2w - 5z

6m + 4m + 3z - 5z + 2w

10m - 2z + 2w

Therefore the answer is 10m -2z + 2w

6 0
3 years ago
The mean hourly wage for employees in goods-producing industries is currently $24.57 (Bureau of Labor Statistics website, April,
SSSSS [86.1K]

Answer:

Step-by-step explanation:

a) H0: \bar x = 24.57

Ha: \bar x \neq 24.57

(Two tailed test at 5% significance level)

b) n=30

Mean difference = 23.89-24.57 = - 0.68

Std error of mean = \frac{s}{\sqrt{n} } \\=\frac{2.40}{\sqrt{30} } \\=0.4382

b) Test statistic t = mean diff/std error = -1.552

df = 30-1 =29

p value=0.0657

c) Since p > 0.05 our signi. level, we accept null hypothesis.

There is no significant difference between the means.

d) Using critical value we find that test statistic is > critical value left

So accept H0

8 0
3 years ago
A stone is thrown vertically upwards with an initial velocity 20m/s. Find the maximum height it reaches and the time taken by it
Gemiola [76]

Answer:

The maximum height it reaches is 20 meters

The time taken by it to reach the height is 2 seconds

Step-by-step explanation:

The formula of the height of the stone is h = u t - \frac{1}{2} g t², where

  • t is the time to reach the height h
  • u is the initial velocity
  • g is the acceleration of gravity

∵ A stone is thrown vertically upwards with an initial velocity of 20 m/s

∴ u = 20 m/s

∵ g = 10 m/s²

→ Substitute them in the equation above

∴ h(t) = 20t - \frac{1}{2} (10) t²

∴ h(t) = 20t - 5t²

→ Arrange the terms of the right side according to the greatest power of t

∴ h(t) = -5t² + 20t

To find the maximum height and the time of it find the vertex of the quadratic function (m, k), where m = \frac{-b}{2a} and k is the value of h at t = m, a is the coefficient of t² and b is the coefficient of t

∵ The coefficient of t² is -5

∴ a = -5

∵ The coefficient of t is 20

∴ b = 20

→ Use them to find h

∵ m = \frac{-20}{2(-5)} = \frac{-20}{-10} = h

∴ m = 2

→ Substitute it in the equation above to find k

∵ h(m) = k

∵ k = -5(2)² + 20(2)

∴ k = -5(4) + 40

∴ k = -20 + 40

∴ k = 20

∴ The coordinate of the vertex of the function are (2, 20)

→ m represents the time of the maximum height and k represents

  the maximum height

∴ The maximum height it reaches is 20 meters

∴ The time taken by it to reach the height is 2 seconds

5 0
3 years ago
A club has 20 women and 17 men and needs to form a committee of six members. How many committees are possible if the committee m
Scorpion4ik [409]

Answer:

2,022,456 committees

Step-by-step explanation:

From the above question, we are given the following information:

Number of women = 20

Number of men = 17

In order to form a committee of six members with at least 2 men, the number of ways we can do this is 5 ways and they are:

a) A committee of 6 men

b) A committee of 5 men and 1 woman

c) A committee of 4 men and 2 women

d) A committee of 3 men and 3 women

e) A committee of 2 men and 4 women

To solve for this we use the combination formula which is given as:

C(n, r) = nCr = n!/r!(n - r)!

Hence, the number of committees that are possible if the committee must have at least two men is calculated as

A committee of 6 men or A committee of 5 men and 1 woman or A committee of 4 men and 2 women or A committee of 3 men and 3 women or A committee of 2 men and 4 women

=[C(17, 6)]+ [C(17,5) × C(20,1)] + [C(17,4) × C(20,2)] + [C(17,3) × C(20,3)] + [C(17,2) × C(20,4)]

= [17!/6!(17 - 6)!] + [17!/5!(17 - 5)! × 20!/1!(20 - 1)!] + [17!/4!(17 - 4)! × 20!/2!(20 - 2)!] + [17!/3!(17 - 3)! × 20!/3!(20 - 3)!] + [17!/2!(17 - 2)! × 20!/4!(20 - 4)!]

= [12376] + [ 6188 × 20] + [2380 × 190] + [680 × 1140] + [ 136 ×4845]

= 2,022,456 committees

5 0
4 years ago
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