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nydimaria [60]
3 years ago
11

Calistoga Produce estimates bad debt expense at 0.50% of credit sales. The company reported accounts receivable and allowance fo

r uncollectible accounts of $476,000 and $1,650 respectively, at December 31, 2020. During 2021, Calistoga's credit sales and collections were $315,000 and $307,000, respectively, and $1,880 in accounts receivable were written off. Calistoga's final balance in its allowance for uncollectible accounts at December 31, 2021, is:
Business
1 answer:
AveGali [126]3 years ago
7 0

Answer:

$1,345

Explanation:

Calculation to determine what Calistoga's final balance in its allowance for uncollectible accounts at December 31, 2021, is

First step is to calculate the Expense amount

Expense=Credit sales $315,000* .5%

Expense=$1,575

Second step is to calculate the Allowance

Allowance 12/31/2020 $1,650

Less Write-offs(1,880)

Allowance ($ 230)debit

Now let calculate the final balance in its allowance for uncollectible accounts

December 31, 2021 allowance for uncollectible accounts= ($230) + $1,575

December 31, 2021 allowance for uncollectible accounts=$1,345

Therefore Calistoga's final balance in its allowance for uncollectible accounts at December 31, 2021, is $1,345

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A firm believes a product’s sales volume (S) depends on its unit selling price (P) as S = $100 – P. The production cost C is $91
Vinvika [58]

Answer:

$45.5

Explanation:

For a firm, profit is equal to total revenue minus total cost. This can be represented mathematically as follows:

π = R - C ................................................................................................... (1)

Where π represents profit, R represents total revenue and C represents total cost.

Total revenue (R) is unit selling price (P) multiply by the sales volume (S). This is represented mathematically as follows:

R = P * S ...................................................................................................... (2)

From the question, sales volume is given as follows:

S = $100 – P .............................................................................................. (3)

We then substitute for S in equation (2) and solve as follows:

R = P($100 – P) = $100P – P^{2} ............................................................... (2a)

From the question, C is given as:

C = $917 + 9S .............................................................................................. (4)

We then substitute for S in equation (4) and solve as follows:

C = $917 + 9($100 – P) = $917 + $900 – 9P = $17 – 9P .................. (4a)

To derive the profit function, the solution for R in equation (2a) and the solution for C in equation (4a) are substituted into equations (1) above and then solved as follows:

π = ($100P – P^{2} ) – ($17 – 9P) = $100P – P^{2} – $17 + 9P

  = $100P + 9P – P^{2} – $17

π  = $109P – P^{2} – $17 ................................................................................ (1a)

Equation (1a) is the profit function. The calculation of the derivative of the profit function (1a) with respect to the price is obtained as follows:

dπ/dP = $109 – 2P = 0 ................................................................................. (5)

From equation (5), we can solve for P as follows:

$109 – 2P = 0

$109 = 2P

2P = $109

P = $109/2

P = $54.5 ............................................................................................................ (6)

To determine the sales volume, we substitute 54.5 in equation (6) for P in the product’s sales volume (S) in equation (3) and we then solve as follows:

S = $100 – $54.5 = $45.5

Therefore, the sales volume (S) at which the firm’s profit is a maximum is $45.5.

5 0
3 years ago
PLEASE HELP ME WITH THIS, THIS IS AN ACTUAL QUESTION FOR ONCE (well multiple)
kati45 [8]

Answer:

I'm not sure how to do this, but I'm assuming if you for the first question go up to ahbeesee and calculate the cost all the way across... you will find your answer.

Explanation:

Basically just use the chart!

HOPE THIS HELPS! :)

4 0
3 years ago
Which of the following will decrease the aggregate quantity of output supplied?
Korvikt [17]
Do you have options..?
3 0
4 years ago
Charlie the cat stole $20 from his cat mom. He's planning on spending the money he stole on catnip (Q1) and dental treats (Q2).
RideAnS [48]

Answer:

$ 20= Q1 (0.5 ) + Q3( 3)

Explanation:

Total Amount = $ 20

Dental treats Q2= $ 3

Catnip Q1= $ 0.50

Maximum no of Dental Treats he can get is = $ 20 /$3= 6.66

If he gets maximum dental treats i.e 6 , $18 will be spent (3*6)

He will be left with = $ 20- $ 18= $ 2

The maximum no of catnip he can get after buying 6 dental treats from $ 2= $ 2/$0.5= 4

Let Q1 denote the catnip and Q3 denote the dental treats then the equation would be like

$ 20= Q1 (0.5 ) + Q3( 3)

So putting the values for q1=0,1,2,3,4,5,6,7,8,9,10

for values 0-4  Q3 will be $ 18

for values 4-6 Q3 will be $ 15

for values 6-8  Q3 will be $ 12

From values Zero on wards the budget constraint will be a slope but after value 4 the change will be after every two points.

The slope will look like the one given in the diagram.

Download docx
6 0
3 years ago
Budgeted sales in Acer Corporation over the next four months are given below: September October November December Budgeted sales
katovenus [111]

Answer:

c. $161,400

Explanation:

The computation of the cash collections for December month is shown below:

Cash sales

= $160,000 × 30%

= $48,000

Credit sales

For same month  = $160,000 × 50% × 70% = $56,000

For one month = $180,000 × 30% × 70% = $37,800

For second month = $140,000 × 20% × 70% = $19,600

So, the total cash collections is

= $48,000 + $56,000 + $37,800 + $19,600

= $161,400

4 0
4 years ago
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