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erastova [34]
3 years ago
6

Cost to store: $140

Mathematics
1 answer:
MrRa [10]3 years ago
8 0

Answer:

175

Step-by-step explanation:

140

140/4=35

140+35=175

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$1689 invested for 4 years at 3% compounded annually ?
Ira Lisetskai [31]

The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901

The amount of money gained after an investment is compounded is given by:

A=P(1+\frac{r}{n} )^{nt}

Where P is principal, A is the final amount, r is the rate, n is the number of times compounded per period and t is the time

Given that P = $1689, t = 4, r = 3% = 0.03, n = 1, hence:

A=P(1+\frac{r}{n} )^{nt}\\\\A=1689(1+\frac{0.03}{1} )^{4*1}\\\\A=\$1901

The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901

Find out more at: brainly.com/question/14295570

5 0
2 years ago
Help can’t find the answer
mixer [17]

Answer:

Volume= 82.4in³

Step-by-step explanation:

Volume is the measure of the amount of space inside of a solid figure, like a cube, ball, cylinder or pyramid. It's units are always "cubic"

To find the volume of sphere, we will use the following formula of Volume:

Volume = 4/3 πr³

Put the values in the formula:

As we know that the value of π is 22/7 or 3.14

Radius = 2.7

According to the formula:

Volume = 4/3 * 3.14 *(2.7)³

Volume= 4/3* 3.14(19.683)

Volume=4/3(61.80462)

Volume=247.21848/3

Volume= 82.4in³....

3 0
3 years ago
Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on
Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

  • If he is given with two kings.
  • If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by =  \frac{^{3}C_2 }{^{47}C_2}   {∵ one king is already there}

              =  \frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}           {∵ ^{n}C_r = \frac{n!}{r! \times (n-r)!} }

              =  \frac{3}{1081}  =  0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by =  \frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}

                                                                   =  \frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}

                                                                   =  \frac{6}{1081}  =  0.0055

Now, probability that he ends up with a full house = \frac{3}{1081} + \frac{6}{1081}

                                                                                    =  \frac{9}{1081} = <u>0.0083</u>.

3 0
3 years ago
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Plzzzzz help 3 9/10 is the same as the sum of 3 1/3 and half of a number what is the number​
kirill [66]

Answer:

9/10 = 1/3 + 1/2x

9/10 - 1/3 = 1/2x

LCM of 10 and 3 is 30

( 27 - 10)/30 = 1/2x

17/30 = 1/2x

17 * 2 = 30x

34=30x

34/30= 30x/30

x = 17/15

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2 years ago
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andrew-mc [135]
Zero exponent is nothing
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3 years ago
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