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2 years ago

Difference between complementary and Supplementary

Mathematics

2 answers:

marishachu [46]2 years ago

6 0

Answer:

See below.

Step-by-step explanation:

Complementary: The sum of 2 angles is 90°.

Supplementary: The sum of 2 angles is 180°

jonny [76]2 years ago

3 0

Complementary angles sum to 90°. Supplementary angles sum to 180°.

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The average of six positive integers starting with a is equal to b. What is the average of five consecutive integers ending with

kvasek [131]

The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.

<h3>What is the average of five consecutive integers ending with b?</h3>

First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;

(a+a+2+a+4+a+6+a+8+a+10)/6 = b

6b=6a+30

b=a+5

Also, let the average of the consecutive intergers ending with b be denoted by; x.

(b+b-1+b-2+b-3+b-4)/5 = x

=(5b-10)/5

=b–2

The average, x=b – 2 (where b = a-5)

Ultimately, the value of the required average is; = a+5-2 = a+3.

Read more on average of integers;

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7 0

11 months ago

Figure A is translated 3 units right and 2 units up. The translated figure is labeled figure B. Figure B is reflected over the x

mojhsa [17]

Answer:

A Is congruent to B and B Is congruent to C

Step-by-step explanation:

Given Figures A, B and C on a coordinate plane with the coordinates below:

Triangle A has points (1, -2), (3, -2), (3, -5).

Triangle B has points (4, 0), (6, 0), (6, -3).

Triangle C has points (4, 0), (6, 0), (6, 3).

The fact that each triangle is a right triangle only shows that the triangles are similar.

For any two shapes to be congruent, they must have in addition to the same shape, the same size.

Therefore, for Triangle A to be congruent to Triangle C, Triangle A must be congruent to Triangle B and Triangle B must be congruent to Triangle C.

7 0

2 years ago

Find the first term of the following geometric sequence ----,42,126,378,1,134

sergey [27]

Since it is a geometric sequence each term will be a specific multiple of the term preceding it, called the common ratio...

126/42=378/126=1134/378=3

The sequence is a(n)=a(3)^(n-1) and we know the second term is 42 so:

42=a(3)^(2-1)

42=3a

a=14

So the first term is 14.

8 0

3 years ago

X=|y| what is the domain and range ?

cricket20 [7]

Answer:

Domain: x ≥ 0

Range: All real numbers

Step-by-step explanation:

This is an absolute value function which creates a V for its graph. Since the absolute value is on y, the function is rotated to the right or sideways.

This means only the x values of 0 and greater are used in the function. Since the domain is the set of all x values then it is x≥0.

This also means that all y values are used on the y-axis. There is no restriction on the y values. Since the range is the set of all y values then it is all real numbers.

5 0

3 years ago

Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B

wariber [46]

Answer:

a. 0.76

b. 0.23

c. 0.5

d. p(B/A) is the probability that given that a student has a visa card, they also have a master card

p(A/B) is the probability that given a student has a master card, they also have a visa card

e. 0.35

f. 0.31

Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

=0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76

b. P(AnBnC')= P(AnB)-P(AnBnC)

=0.3-0.07= 0.23

c. P(B/A)= P(AnB)/P(A)

=0.3/O.6= 0.5

e. P((AnB)/C))= P((AnB)nC)/P(C)

=P(AnBnC)/P(C)

=0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

=(P(AnC) U P(BnC))/P(C)

=(0.11+0.1)/0.2

=0.21/0.2 = 0.31

7 0

2 years ago