To find the area of the arena, you will need to find the areas of the rectangular spaces and the 2 semicircles. Because the formulas are given, I will just substitute in the values and show the work for finding the areas.
To find the perimeter, you will look at the distances of lines that take you around the space. Because two of these spaces are half circles, you will need to find the circumference of the full circle.
Also, the answers need to be given in meters, so all units given in centimeters will be divided by 100 to convert them to meters.
Perimeter:
C= 3.14 x 20 m
C = 62.8 meters
62.8 + 8 + 25 + 8 + 5 + 8 + 10 + 8 + 40= 174.8 meters for the Perimeter
Area:
A = 25 x 8
A = 200 square meters
A = 10 x 8
A = 80 square meters
A = 20 x 40
A = 800 square meters
A = 3.14 x 10^2
A = 314 square meters
Total Area: 314 + 800 + 80 + 200= 1394 square meters
Answer:
( 11 -6)
( -5 6 )
Step-by-step explanation:
Multiply the first row of N by first column of M. This will give the first element in top row of the answer :-
-3*-2 + 1*5 = 11
Then multiply the first row in N by the second column of M to give the second element of the top row.
-3*0 + 1*-6 = -6
Then do a similar process with the second row in N.
J time sixteen equals thirty five.
.03 time 72 then add 72 or just do 1.03 time 72
Answer:
Step-by-step explanation:
This is an order of operations question. First in PEMDOS you want to do your parenthesis, turn (5-2) into 3,
15 ÷ 3 + 4
Then do your divison, turning 15 ÷ 3 into 5
5 + 4
Then finish with 5 + 4
The answer is 9
