Answer:
3 grams
Step-by-step explanation:
We are going to take the mass of a bunch of little strips below the triangle "roof." To do this, we must figure out what formula for the mass we'll use, in this case, we'll use:
Mass of strip = denisty * area = (1+x)*y*deltax grams
now, because the "roof" of the triangle contains two different integrals (it completely changes direction), we will use TWO integrals!
**pretend ∈ is the sum symbol
Mass of left part = lim x->0 ∈ (1+x)*y*deltax = inegral -1 to 0 of (1+x)*3*(x+1) = 3 * integral -1 to 0 of (x^2 + 2x + 1) = 3 * 1/3 = 1
Mass of left part = lim x->0 ∈ (1+x)*y*deltax = inegral 0 to 1 of (1+x)*3*(-x+1) = 3 * integral 0 to 1 of (-x^2 + 1) = 3 * 2/3 = 2
Total mass = mass left + mass right = 1 + 2 = 3 grams
13, each term is the sum of two preceding ones.
Answer:
238
Step-by-step explanation:
299+428-62-106-126-195
727-62-106-126-195
665-106-126-195
559-126-195
433-195
238
30°, 70°, and 80°.
It is an acute-angled triangle.
Explanation:
The ratio of the measures of ∠s in Δ is 3:7:8.
So, let us suppose that the measures are, 3k, 7k, 8k.
Evidently, their sum is
180°.
3k+7k+8k=180
18k=180
k= 10
Hence, the measures are,
30°, 70°, and 80°.
As all the angles are acute, so is the triangle.
Answer:
I dont remember how to do this but i wish you luck, try searching on khan academy for how to do this ;)
Step-by-step explanation:
