1.275 x 10 to the second power
In scientific notation, you move the decimal place until you have a number between 1 and 10. Then you add a power of ten that tells how many places you moved the decimal. In scientific notation, so 127.5 becomes 1.275 x 10 to the second power.
Source: https://www.infoplease.com/math-science/mathematics/numbers-formulas/scientific-notation
Answer:
A and B
Step-by-step explanation:
Nadeen started with 18 tokens and will lose 3 with every game he/she/they play.
The equation that would represent this is a) 18 - 3x. b, when distributed, is also 18 - 3x.
3(6 - x) ---> multuply 3 with 6 and 3 with x
18 - 3x
<h2>skip to answer 6</h2>
Answers To The Whole Assignment
1. middle graph
2. middle graph
3. in e^3 = 3, in e^2y=2y
4. in e^ln1=1, in e^ln5x=5x
5. A. In2
6. A. In4
7. B. ln a + 2 ln b C. ln a2 + ln b2 - ln a E. ln ab2
8. C. ln 25x + ln 1 D. ln 25x
9. In 3x= in3+ln x= in In 2a/b= In2+ln a-lnb
10. A. 4 ln 2 + 4 ln x B. ln 4 - 2 ln x + 5 ln y
11. A. x=5 B. x=6
12. C. {8} B. {3}
13. 5
14. Since 0 in ln(3x) - 0 is not a logarithm, the property of logarithms cannot be used here.The difference shown cannot be written as a quotient of logarithms.The step ln(x2) = ln(3x) - (0) reduces to
ln(x2) = ln(3x).The possible solutions are 0 and 3, with 0 being extraneous.
The second shape is 3 times bigger than the first which means side DA is 45cm long.
Let t and s represent the masses of 20% and 60% alloys respectively.
t+s=80, s=80-t
(0.2t+0.6s)/80=0.52 multiply both sides by 80
0.2t+0.6s=41.6, now using s=80-t in this equation gives us:
0.2t+0.6(80-t)=41.6 perform indicated multiplication on left side
0.2t+48-0.6t=41.6 combine like terms on left side
-0.4t+48=41.6 subtract 48 from both sides
-0.4t=-6.4 divide both sides by -0.4
t=16, since s=80-t
s=64
So 16kg of 20% alloy is mixed with 64kg of 60% allow to make 80kg of a 52% alloy.