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3 years ago

Find the points which divide the line segment joining the points (0, -3) and (7,1) in the ratio 2:3

Mathematics

1 answer:

rewona [7]3 years ago

3 0

Answer:

Known two points, list function expression, use

$y-y_{0}=k(x-x_{0})$

$k= \frac{y_{2} -y_{1\\}}{x_{2} -x_{1} }$

The function expression is

$y=\frac{4}{7}x-3$

It is known that the cross section of two points is 7, so the point of 2:3 is 14 / 5, that is, 0 + 14 / 5 is the abscissa of the point, which is substituted into the original equation to get y = - 7 / 5.

So the result is $(\frac{14}{5} ,-\frac{7}{5} )$

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2 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

Answer:

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

Solution:

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

6 0

3 years ago

Recall that the volume of a sphere is given by the formula V = 4/3pi to the 3rd

Kisachek [45]

9514 1404 393

Answer:

1. (256/3)π ft³

2. 33.49 ft³

Step-by-step explanation:

1. Put 4 ft into the formula where r is, then simplify.

V = (4/3)π(4 ft)³ = (256/3)π ft³

2. The radius is half the diameter, so is 2 ft. Put that in the formula, along with the value for π, and do the arithmetic.

V = (4/3)(3.14)(2 ft)³ ≈ 33.49 ft³

4 0

3 years ago