Answer:
$ 5674.076
Step-by-step explanation:
The question is on compound interest
The formulae = A= P(1+ r/n) ^nt .......where P is the principal amount, r is the rate of interest in decimal, n is number of compoundings per year and t is the total number of years.
Given; P= $4,000.00 , r=12/100=0.12, n=2 and t=3
Substituting values in the equation A= P(1+ r/n) ^nt
A= 4000 ( 1+0.12/2)^2×3
A=4000(1.06)^6
A=$ 5674.08
Am sorry I try but I cant
<span>2x-3y=3
3y = 2x - 3
y = 2x/3 - 1
hope it helps</span>
Answer:
P(A) = 0.49
Step-by-step explanation:
Given:
A and B are mutually exclusive events.
P(B) = 0.03
P(A or B) = 0.52
If two events A and B are mutually exclusive events, then there are no elements common in both the events. So, the probability of their intersection is 0.
Now, as per probability addition theorem:
P(A or B) = P(A) + P(B) + P(A and B)
For mutually exclusive events, P(A and B) = 0. So,
P(A or B) = P(A) + P(B) + 0
P(A or B) = P(A) + P(B)
Plug in the given values and solve for P(A). This gives,
0.52 = P(A) + 0.03
P(A) = 0.52 - 0.03
P(A) = 0.49
Therefore, the probability of occurrence of event A is P(A) = 0.49.
