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jek_recluse [69]
3 years ago
9

Find the highest common factor of 72 and 135

Mathematics
2 answers:
kap26 [50]3 years ago
6 0

Answer:

9

Step-by-step explanation:

9 is the highest common factor of 72 and 135

andrey2020 [161]3 years ago
4 0

Answer:9

Step-by-step explanation:

Find the prime factorization of 72

72 = 2 × 2 × 2 × 3 × 3

Find the prime factorization of 135

135 = 3 × 3 × 3 × 5

To find the GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 3 × 3

GCF = 9

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7(2+5v)=3v+14 can anyone help???
arsen [322]
7(2+5v)=3v+14
14+35v=3v+14
-3v -3v
14+32v=14
-14 -14
32v=0
÷32 ÷32
v=0

hope this helps!!
5 0
3 years ago
Read 2 more answers
What are the zeros of the function below? Check all that apply.
galina1969 [7]

Answer:

x = 3 or x = 2 or x = -1 or x = -5

Step-by-step explanation:

Solve for x:

((x - 3) (x - 2) (x + 1) (x + 5))/x = 0

Multiply both sides by x:

(x - 3) (x - 2) (x + 1) (x + 5) = 0

Split into four equations:

x - 3 = 0 or x - 2 = 0 or x + 1 = 0 or x + 5 = 0

Add 3 to both sides:

x = 3 or x - 2 = 0 or x + 1 = 0 or x + 5 = 0

Add 2 to both sides:

x = 3 or x = 2 or x + 1 = 0 or x + 5 = 0

Subtract 1 from both sides:

x = 3 or x = 2 or x = -1 or x + 5 = 0

Subtract 5 from both sides:

Answer:  x = 3 or x = 2 or x = -1 or x = -5

8 0
3 years ago
Read 2 more answers
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:10 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acce
Daniel [21]

Answer: If we define 2:00pm as our 0 in time; then:

at t= 0. the velocity is 30 mi/h.

then at t = 10m (or 1/6 hours) the velocity is 50mi/h

Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:

a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/h^{2}

Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)

So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/h^{2}

5 0
3 years ago
2852.1 round to nearest tenth
Kamila [148]
The number 2852.1 is already rounded to the tenth since the tenth place is one place to the right of the decimal
6 0
3 years ago
Lara planted some seeds. For every 3 seeds Lara planted, only 2 seeds grew.
Tresset [83]

Given:

For every 3 seeds Lara planted, only 2 seeds grew.

Altogether, 12 seeds grew.

To find:

The number of total seeds planted by Lara.

Solution:

It is given that for every 3 seeds Lara planted, only 2 seeds grew. It means the ratio of total seeds planted to seeds grew is 3:2.

Altogether, 12 seeds grew.

Let x be the number of total seeds planted by Lara. Then,

x:12=3:2

\dfrac{x}{12}=\dfrac{3}{2}

x=\dfrac{3}{2}\times 12

x=18

Therefore, the total number of seeds planter by Lara is 18.

3 0
3 years ago
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