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Vesna [10]
2 years ago
14

ALGEBRA 2 PLEASE HELP! QUICKLY!! I AM TERRIBLE AT ALGEBRA AND I HAVE LOADS OF STUFF TO Do TODAY CAN YOU PLEASE HELP ME WITH THIS

?? PLEASE EXPLAIN TO ME WHAT THE CORRECT ANSWERS ARE AND HOW TO GET THEM IN PREPARATION FOR THE UNIT TEST!

Mathematics
1 answer:
Genrish500 [490]2 years ago
4 0
A) the posible roots of the function f(x)=x⁴-3x³-5x²+21x+22 are: 
=-1,+1,-2,+2,-11,+11,-22+22.

b)
one zero of the funtion can be: x=-1 ⇒y=0   (-1,0)

c)
other zero of the funtion is: x=-2 ⇒y=0  (-2,0)

d)
if x=0 then y=22   (0,22)

e) In the file is the graph. 


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Abe is planning on spending at most 27% of his monthly income on housing. What is the most he can spend if his he makes $71,614
Mademuasel [1]

Answer:

84,000

Step-by-step explanation:

Here is why

1. cuz im a genuis

2. your dumb

3. you suck at math

4. if your a girl you can suck this big fat d*** and shove it down your mouth

4 0
3 years ago
Jan noticed at the store that a sweater costs $3.95 more than a shirt. she bought 3 shirts and 2  sweaters and the total costs (
grandymaker [24]
Lets say the price of a shirt is X, then the price of sweater is X + 3.95

Since a total cost is 71.65 for 3 shirts and 2 sweaters. 71.65 = (3*X) + 2*(X+3.95)

So, 71.65 = 3X + 2X + 7.9

71.65 - 7.9 = 5X

12.75 = X. Therefore, the price of a shirt is 12.75 dollars, and the price of a sweater is 16.7 dollars (12.75 + 3.95)

** 
5 0
2 years ago
1. A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts o
Sauron [17]

Answer:

The confidence interval estimate of the population mean is :

(0.61 ppm, 0.90 ppm)

The correct option is (A).

Step-by-step explanation:

The amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city are:

S = {0.58, 0.82, 0.10, 0.98, 1.27, 0.56, 0.96}

A (100-\alpha )\% confidence interval for the population mean (μ) is an interval estimate of the true value of the mean. This interval has a (100-\alpha )\% probability of consisting the true value of mean.

⇒ Since the population standard deviation is not provided we will use the <em>t</em>-distribution to construct the 99% confidence interval for mean.

⇒ The formula for confidence interval for the population mean is:

                                          \bar x\pm t_{\alpha/2,(n-1)}\times \frac{s}{\sqrt{n}}

Here,

\bar x = sample mean

<em>s </em>= sample standard deviation

<em>n</em> = sample size

t_{\alpha/2,(n-1)} = critical value.

The degrees of freedom for the critical value is, (<em>n</em> - 1) = 7 - 1 = 6.

The significance level is: \alpha =1-Confidence\ level=1-0.99=0.01

The critical value is:

t_{\alpha/2,(n-1)}=t_{0.01/2, 7}=t_{0.05,7}=3.143

**Use the <em>t</em>-table for the critical value.

Compute the sample mean and sample standard deviation as follows:

\bar x=\frac{1}{7}(0.58+ 0.82+ 0.10+ 0.98+ 1.27+ 0.56+ 0.96) =0.753

\int\limits^a_b {x} \, dx s=\sqrt{\frac{\sum (x{i}-\bar x)^{2}}{n-1} } =\sqrt{\frac{1}{6} \times 0.859743} =0.379

The 99% confidence interval for μ is:

x^{2} CI=0.753\pm 3.143\times\frac{0.379}{\sqrt{7}} \\=0.753\pm0.143\\=(0.61, 0.896)\\\approx(0.61, 0.90)

The confidence interval estimate of the population mean is:

(0.61 ppm, 0.90 ppm)

The upper and lower limit of the 99% confidence interval indicates that the true mean value is less than 1 ppm. This implies that there is not too much mercury in tuna sushi

Because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.

Thus, the correct option is (A).

6 0
3 years ago
Help pleaseeeeeeeeeeeeeeeeeeeeeee
sasho [114]

Answer:

1/5 pound

I just did this on paper and got 1/5 pound (23/40)

6 0
2 years ago
Find the differential equation of the family of tangent lines to the parabola y^2 = 2x
dusya [7]
\bf &#10;y^2=2x\implies y=\sqrt{2x}\implies y=x^{\frac{1}{2}}&#10;\\ \quad \\&#10;\cfrac{dy}{dx}=\boxed{?}
5 0
3 years ago
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