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Vesna [10]
2 years ago
14

ALGEBRA 2 PLEASE HELP! QUICKLY!! I AM TERRIBLE AT ALGEBRA AND I HAVE LOADS OF STUFF TO Do TODAY CAN YOU PLEASE HELP ME WITH THIS

?? PLEASE EXPLAIN TO ME WHAT THE CORRECT ANSWERS ARE AND HOW TO GET THEM IN PREPARATION FOR THE UNIT TEST!

Mathematics
1 answer:
Genrish500 [490]2 years ago
4 0
A) the posible roots of the function f(x)=x⁴-3x³-5x²+21x+22 are: 
=-1,+1,-2,+2,-11,+11,-22+22.

b)
one zero of the funtion can be: x=-1 ⇒y=0   (-1,0)

c)
other zero of the funtion is: x=-2 ⇒y=0  (-2,0)

d)
if x=0 then y=22   (0,22)

e) In the file is the graph. 


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Find the missing side lengths​
AURORKA [14]

Answer:

X = 18

Y = 9√3

Step-by-step explanation:

use sin equation for right angle triangle

The sine of the angle

= ( the length of the opposite side ÷ the length of the hypotenuse.)

according to this question,

sin 30 = 9 / X

1/2 = 9 / X

X = 18

use cosine to find y

The cosine of the angle

= (the length of the adjacent side ÷ the length of the hypotenuse.)

cos 30 = y/x

√3/2 = y/ 18

y = 9 ✓3

5 0
2 years ago
Which inequality makes the statement below true? |-13 BLANK -13 O A. = O B. < OC. S O D. >
navik [9.2K]

Answer:

Hey there the best answer would be A.=

Step-by-step explanation:

3 0
2 years ago
4. Because the triangles are congruent, the area of the entire
nordsb [41]

Answer:5

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
3 years ago
What is the exact value for the expression the square root of 52− the square root of 13 + the square root of 117 ? Simplify if p
avanturin [10]

√52 -√13 +√117

= 2√13 -√13 +3√13

= 4√13 . . . . matches selection A

_____

√52 = √(4·13) = (√4)(√13) = 2√13

√117 = √(9·13) = (√9)(√13) = 3√13

8 0
3 years ago
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