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jeka94
3 years ago
5

How do you write an equation of a line that passes through (4,3) and has a slope of 2?

Mathematics
2 answers:
lana66690 [7]3 years ago
5 0

Answer:

y = 2x - 5

Step-by-step explanation:

y-intercept form is y = mx + b, where m is the slope and b is the y-intercept. We know the slope is 2, so all that's left is to find the y-intercept. To do this, for every 1 we subtract from x in (4,3), we take away 2 from y because the slope is two. We keep doing this until x is zero. The remaining y-value is the y-intercept.  

agasfer [191]3 years ago
5 0

Answer:

y = 2x-5, see below.

Step-by-step explanation:

There is enough information to make a point slope equation that we can later convert into slope intercept.

Point slope form is:

y-y_1=m(x-x_1)

(x_1,y_1): \text{A point.} \\\\m - \text{Slope.}

We are given the slope of 2 and the point (4,3).

Replace the variables with the given information.

y-y_1=m(x-x_1)\rightarrow y-3=2(x-4)

With the equation we will now convert it into slope intercept form:

y-3=2(x-4)\\\\y-3=2x-8\\\\y-3+3=2x-8+3\\\\\boxed{y=2x-5}

Hope this helps!

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Steps
First, divide x^3 - 5x^2 + 3x - 8/x - 3: x^3 - 5x^2 + 3x - 8/x - 3 = x^2 + -2x^2 + 3x -8/x - 3
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Second, divide -2x^2 + 3x - 8/x - 3: -2x^2 + 3x - 8/x - 3 = -2x + -3x - 8/x - 3
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Lastly, simplify
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