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3 years ago

1×1+9×(1/100)+1 ×(1/1,000)

2 answers:

8 0

Using PEMDAS
P = 1x1+9x(0.01)+1x(0.001)
E = no change
M = 1+0.09+0.001
D = no change
A = 1.091
S = no change
final answer is 1.091

WINSTONCH [101]3 years ago

6 0

Answer:

1.091 because of PEMDAS or (parentheses) $x^{2}$ exponents, *multiplication, / division + addition - subtraction

Step-by-step explanation:

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3 years ago

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3 years ago

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Determine the domain and range of the function f(x)= 3x+2. Also, state the intervals where the function f(x)= 3x+ 2 is increasin

aev [14]

Answer:

Increasing on it's domain $(-\infty,\infty)$ because the slope is positive.

The domain and range are both all real numbers, also known as

$(-\infty,\infty)$ .

Step-by-step explanation:

All domain really means is what numbers can you plug in and you get number back from your function.

I should be able to plug in any number into 3x+2 and result in a number. There are no restrictions for x on 3x+2.

The domain is all real numbers.

In interval notation that is $(-\infty,\infty)$ .

Now the range is the set of numbers that get hit by y=3x+2.

Well y=3x+2 is a linear function that is increasing. I know it is increasing because the slope is positive 3. I wrote out the positive part because that is the item you focus on in a linear equation to determine if is increasing or decreasing.

If slope is positive, then the line is increasing.

If slope is negative, then the line is decreasing.

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3 years ago