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Talja [164]
2 years ago
9

I WILL GIVE BRAINLY PLEASE HELP ITS THE TOP ONE

Mathematics
1 answer:
Anastasy [175]2 years ago
5 0

Answer:

I think it is C

Step-by-step explanation:

Forgive me if I am wrong the reason I think so is  I did one like this last week. Sorry if it is wrong trying to remember.

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Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
6 0
2 years ago
5u^2 + 6 = -13u please help
Komok [63]

Answer:

u = -2, -3/5

General Formulas and Concepts:

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Factoring
  • Finding roots

Step-by-step explanation:

<u>Step 1: Define equation</u>

5u² + 6 = -13u

<u>Step 2: Solve for </u><em><u>u</u></em>

  1. Rewrite:                    5u² + 13u + 6 = 0
  2. Factor:                      (u + 2)(5u + 3) = 0
  3. Find roots:                u = -2, -3/5
5 0
2 years ago
(((click on the image to see it all))))<br><br>I need the answers to number 2 and 4 asap​
Digiron [165]

Answer:

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3 0
2 years ago
Which expression is equivalent to (^5sqrt3^2)^1/3
11Alexandr11 [23.1K]

Answer:

3^2/15

Step-by-step explanation:

(^5sqrt3^2)^1/3

(3^2/5)^1/3

multiply the powers

3^2/5*1/3

3^2/15

6 0
3 years ago
Find c.<br> Round to the nearest tenth:<br> 2 cm<br> 15°<br> 105
Anit [1.1K]

Answer:

0.5cm

Step-by-step explanation:

Using the sine rule

4 0
2 years ago
Read 2 more answers
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