Perpendicular lines are lines that cross at a 90 degree angle
Lines AB and BC
Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
Answer:
9) C. 35 + 0.12x = 44.36
10) B
11) A. 32
Step-by-step explanation:
9)
44.36 is the TOTAL so the equations have to EQUAL it.
PER mile means it's a variable so it's 0.12x:
35 is a constant so there's no variable attached:
35 + 0.12x = 44.36
10)
B because you have to cancel the y values and to do that, you multiply the 1st equation by 3.
11)
0.1x + 0.25(46 - x) = 6.70
0.1x + 11.5 - 0.25x = 6.7
-0.15x = 6.7 - 11.5
-0.15x = -4.8
x = 32
Answer:
900m or 300m
Step-by-step explanation:
45 x 20 = 900
30 x 10 = 300
