All categories

2 years ago

Dan has £100. Colin takes £. How much is left

Mathematics

2 answers:

sasho [114]2 years ago

8 0

Answer:

Maybe 99£

Step-by-step explanation:

Please give me brainliest

mihalych1998 [28]2 years ago

7 0

Answer:

i think 99 because theres no number after the symbol

Step-by-step explanation:

You might be interested in

Please help I need to get this done

hichkok12 [17]

Answer:

Step-by-step explanation:

So you take 7x-92+6x+12=180

And then you get x=20

Plug in 20 for x for <LOM

And you get and you get 48

Hope this helped!!

3 0

3 years ago

Pls can someone help me<br><img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7

Firlakuza [10]

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

6 0

3 years ago

What numbers less than 200 are divisble by 4 but not 12

kolezko [41]

Answer:

There are 48 numbers that satisfy the condition

Step-by-step explanation:

Find the relationship between 3 and 12

3 * 4 = 12

The maximum number of multiples of 12 within 200 is 18.

The maximum number of multiples within 200 is 66.

So the number of numbers within 200 that go exactly into 3 but not exactly into 12 is:

66-18 = 48

3 0

2 years ago

Kate borrowed $400 from her friend. she will repay this amount plus 3 percent simple interest after one year. what is the total

timama [110]

3% = .03

400 • .03 = 12

400 + 12 = $412.00

4 0

3 years ago

Help me please ASAP

Mashutka [201]

Answer: $\frac{5}{35}$

Step-by-step explanation:

Since, the total number of contestant = 7,

Thus, the probability that out of 3 contestant, me and my friend is chosen

= $\frac{2_C_2\times 5_C_1}{7_C_3}$

= $\frac{\frac{2!}{2!0!}\times \frac{5!}{1!\times 4!}}{\frac{7!}{4!\times 3!}}$

= $\frac{1\times 5}{\frac{7\times 6\times 5\times 4!}{4!\times 6}}$

= $\frac{5}{35}$

⇒ Third Option is correct.

4 0

3 years ago