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Margarita [4]
3 years ago
7

Cynthia invests some money in a bank which pays 5% compound interest per year.

Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Answer:

£6956.52

Step-by-step explanation:

Given data

R=5%

A= £8000

T= 3 years

P=???

The compound interest is

A=P(1+r)^t

8000= P(1+0.05)^3

8000= P(1.05)^3

8000= P1.15

P= 8000/1.15

P=6956.52

Hence she needs to invest £6956.52

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Which of the following statements is not​ true? Choose the correct answer below. A. Similar triangles have the same shape and si
valentina_108 [34]

Answer:

D. If two triangles are​ similar, then there exists a constant k greater than or equals 1 which is equal to the ratio of the lengths of corresponding sides.

Step-by-step explanation:

Two triangles are similar if their corresponding angles are the same size. They need not be of the same length but the corresponding sides should be of the same proportion. One may be bigger that the other but the ratio of the lengths of corresponding sides will be equal. They may also be mirror images of one another so they will essentially have the same shape.

7 0
3 years ago
Pls help me I give brainliest thank uu and can u do step by step
Phoenix [80]

Answer:

A. 48,000

Step-by-step explanation:

60 x 20= 1200

1,200 x 40= 48,000

Plz mark brainliest .^.

6 0
4 years ago
Read 2 more answers
Can someone help me with this question please.
drek231 [11]

Answer:

a). 3a² + 17a - 1

b). 4y (7y-6)

Step-by-step explanation:

in the second question, we find a number that can divide 28 and 24 without a remainder, which is 4

3 0
3 years ago
A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per
Tems11 [23]

Answer:

The pressure is changing at \frac{dP}{dt}=3.68

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} and we want to find at what rate is the pressure changing.

The equation that model this situation is

PV^{1.4}=k

Differentiate both sides with respect to time t.

\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)

Apply this rule to our expression we get

V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0

Solve for \frac{dP}{dt}

V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}

when P = 23 kg/cm2, V = 35 cm3, and \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} this becomes

\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68

The pressure is changing at \frac{dP}{dt}=3.68.

7 0
4 years ago
For children between the gages of 10 months and 298 months, there is an approximately linear relationship between height and age
Alex787 [66]

Answer: 987

Step-by-step explanation:

6 0
2 years ago
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