48 wooden pre-sharpened pencils cost $1.88. How much does EACH pencil cost?
1 answer:
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I'll help with number 5 since number 4 is a bit too small and squished to read.
Check out the attached image below for the full two-column proof. The added entries are in red.
The given statement is basically what the teacher shows at the top of the problem, which is the fact that angle 5 and angle 2 are congruent. You just repeat this statement.
The reason for statement 2 is that angle 2 and angle 4 are vertical angles. They are opposite angles formed by a pair of intersecting lines. This is the vertical angle theorem at work. We'll use the vertical angle theorem again for statement 4 when we say that angle 5 and angle 8 are the same measure.
The transitive property comes into play when we connect angles 2, 5, and 4 together, which helps us get line 3. We also connect angles 4, 5 and 8 together to get the last line, which is why the reason for statement 5 is "transitive property"
Answer:
Step-by-step explanation:
The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be . The magnitude of
will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is
, we have:
(Recall that
)
Now that we've found the vertical component of the velocity and launch, we can use kinematics equation to solve this problem, where
is final and initial velocity, respectively,
is acceleration, and
is distance travelled. The only acceleration is acceleration due to gravity, which is approximately
. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.
What we know:
Solving for :