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3 years ago

Can someone find the domain and range in this graph i’m having trouble

Mathematics

1 answer:

Westkost [7]3 years ago

8 0

To find the domain of graph, we notice at the point on the left and the right.

Domain is the set of all x-values, so we perceive in a horizontal line or x-axis.

The first point on left is at x = -1 and the second point on the right is at x = 1.

Since the points are opened and therefore, the Inequality signs can only be > or <.

Therefore, the domain is -1 < x < 1

To find the range, similar to domain but we perceive vertical line or y-axis. Range is the set of all y-values.

We notice that the minimum point is -1 or y = - 1 and maximum point at 1 or y = 1.

Therefore, the range is -1 < y < 1

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Scilla [17]

Answer:

Step-by-step explanation:

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3 years ago

KonstantinChe [14]

<h2> QUESTION # 1</h2>

Answer:

Total distance = 21 units (meters)

The average speed = 7 meter per second.

Step-by-step explanation:

To Determine:

If the whole run took the bug 3 seconds, what was its average speed?

Information Fetching and Solution Steps:

A beetle was running along a number line.

The beetle ran from 4 to 25.

Let suppose each unit on a number line represents 1 meter.

As the beetle ran from 4 to 25, so

the distance covered by beetle is:

25 - 4 = 21 units. i.e. 21 meters

As the average speed can be determined by dividing the total distance by the total time, so

The average speed = total distance / total time

Total distance = 21 units (meters)

Total time = 3 seconds

The average speed = total distance / total time

= 21/3

= 7 meter per second

Therefore, the average speed = 7 meter per second.

<h2> QUESTION # 2</h2>

Answer:

Total distance = 54 units (meters)

The average speed = 6 meter per second.

Step-by-step explanation:

To Determine:

If the whole run took the bug 9 seconds, what was its average speed?

Information Fetching and Solution Steps:

A beetle was running along a number line.

The beetle ran from 24 to 78.

Let suppose each unit on a number line represents 1 meter.

As the beetle ran from 24 to 78, so

the distance covered by beetle is:

78 - 24 = 54 units. i.e. 54 meters

As the average speed can be determined by dividing the total distance by the total time, so

The average speed = total distance / total time

Total distance = 54 units (meters)

Total time = 9 seconds

The average speed = total distance / total time

= 54/9

= 6 meter per second

Therefore, the average speed = 6 meter per second.

6 0

3 years ago

Jose earned 29.75 in 3.5 hours how much did he earn in one hour

baherus [9]

Answer:

$8.50

Step-by-step explanation:

$29.75 / 3.5 hours = $8.50 per hour

6 0

3 years ago

Read 2 more answers

Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65

erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 2.65

$\sigma$ = standard deviation = 0.85

n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

P(X bar <= 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z < 2.06) = 0.98030

P(X bar <= 2.65) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .

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3 years ago

Solve 7.8+3.5w-1.5 for w = 6.8 using PEMDAS

VikaD [51]

7.8+3.5(6.8)-1.5
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31.6-1.5
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