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Crazy boy [7]
3 years ago
6

1. Find three consecutive odd integers such that the sum of twice the smallest and 4 times the largest is 61.

Mathematics
1 answer:
Anna [14]3 years ago
8 0

Answer:

hjhxhkhjknhhhjnvhfjkjh

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Paul is thinking of a number.
Ierofanga [76]
The answer is 3 and 9.
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How many solutions does 0.75(x+40)=0.35(x+20)+0.35(x+20) have?
Neporo4naja [7]
Only one because there is one variable and the combined coefficients of x are non-zero.
(0.75(x+40)=0.70(x+20), 0.05x=14-30=-16, x=-320)
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jasenka [17]
W= 3.2

Need explaining?
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F(1) = 5
MatroZZZ [7]

Answer:

a(7)=3645

Step-by-step explanation:

you have :

f(1) =a= 5

and from recursive rule: f(n) = r · f(n − 1) and f(n) = 3 · f(n − 1)

So r=3

then

a(n)=a*r^(n-1)

a(7)=5*3^(7-1)

a(7)=5*3^6=3645

<em>hope this helps</em>

<em />

7 0
3 years ago
Two students have examined the scatter plot shown and have created a line of best fit for the data. Student A believes that the
svlad2 [7]

Answer:

usbksnkwojeybnakusbmsonsnllonsybks maobsji ..isbksobsniysnwk9mnsubsnnkiaba inahjans ishksksubs iga6kakoav oaujskoa oshkaous oao8nahks phnaian. isynkalubs ouanamlsubsla usvkslisns kaibsmsobsusbkiagnsoyns ia7hkw0me7a ushkoia isjhajskybs ihebsjjs7ja iushsjka7hanla

Step-by-step explanation:

somnkeunmaonuhbsib m isbniakks jjshkwhbsj iksne

ajbsubks8 laibsyjs obsujbsk isgis8j s osjins kksuusb kbsuajoao. kwunkaohw iwhjnwkbjsjsjkwjnao oshjsklsuns

8 0
3 years ago
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