Answer:
AB ≈ 14.3
Step-by-step explanation:
We're given <em>two sides </em>(BC and CA) and an <em>angle </em>(C)<em> between them</em>; the <em>law of cosines </em>is a good tool for calculating the third side of the triangle here. To remind you, the law of cosines tells us the relationship between the sides of a triangle with side lengths a, b, and c:
Where C is the angle between sides a and b. c is typically the side we're trying to find, so on our triangle, we have
Substituting these values into the law of cosines:
Answer:
x = 5
Step-by-step explanation:
To solve this, we just have to the multiplication and do the simplification (adding up the similar terms) afterwards:
3(x+1)=7(x-2)-3 becomes...
3x + 3 = 7x - 14 - 3
3x + 3 = 7x -17
Then we move all x's on one side and all plain numbers on the other side, we'll move the x's to the right since there's a bigger value there, and will move the plain numbers on the left side, by subtracting 3x and by adding 17 on both sides
3x + 3 - 3x + 17 = 7x -17 + 17 - 3x
20 = 4x
If we isolate x alone we have:
20/4 = x or x = 5
Answer:
YZ = 38
Step-by-step explanation:
Corresponding parts of congruent triangles are equal.
YZ = WZ
YZ = 38
Answer:
The initial cost is $20, and it adds $5per hour
Step-by-step explanation:
Read the graph
Answer:
the areas of these triangles are 83.2cm² and 46.8cm²
Step-by-step explanation:
1. If the triangles are similar and the ratio of the perimeter ois 4:3, then the areas are in the following ratio:
4²:3²
16:9
2. The sum of their areas is 65 cm², then, you can calculate the area of the larger triangle as following:
130(16/16+9)
130(0.64)
=83.2cm²
3. The area of the smaller triangle is:
130(9/16+9)
130(0.36)
46.8cm²
<u>Hope this help</u>s
