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dem82 [27]
2 years ago
8

Factorise fully 12x³ - 30x²​

Mathematics
1 answer:
MariettaO [177]2 years ago
5 0

Answer:

6x² (2x - 5)

Step-by-step explanation:

12x³ - 30x²

= 6x² (2x - 5)

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An office supply store recently sold a black printer ink cartridge for $17.99 and a color printer ink cartridge for $20.99. At t
UNO [17]

Answer:

40 black ink cartridges and 19 colored ink cartridges

Step-by-step explanation:

Let b represent the number of black printer ink cartridges sold. Let c represent the number of color printer ink cartridges sold.

Set up a system of equations:

\displaystyle\\\begin{cases}b+c=59\\17.99b+20.99c=1,118.41\end{cases}

b+c=59\implies b=59-c

Substitute:

\displaystyle\\17.99(59-c)+20.99c=1,118.41\\\implies c=\boxed{19}

\implies b+19=59\implies b=\boxed{40}

⇒ 40 black ink cartridges, 19 colored ink cartridges (ans)

8 0
2 years ago
Idek the answer please help
VashaNatasha [74]

Answer:

A.

Step-by-step explanation:

4 0
2 years ago
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Can someone help me out please
Svetach [21]

Answer:

area = (14 x 16) - (0.5 x 16 x 6) = 176 ft²

Step-by-step explanation:

8 0
3 years ago
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Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
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Click here for 5 f.r.e.e. points... and maybe free Brainliest as well :1
Novay_Z [31]

Answer:

hello thanks for the f.r.e.e points saving

to give 100 Satep-by-step explanation:

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3 years ago
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