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damaskus [11]
4 years ago
7

Suppose you just purchased a digital music player and have put 15 tracks on it. After listening to them you decide that you like

3 of the songs. With the random feature on your​ player, each of the 15 songs is played once in random order. Find the probability that among the first two songs played
​(a) You like both of them. Would this be​ unusual?

​(b) You like neither of them.

​(c) You like exactly one of them.

​(d) Redo​ (a)-(c) if a song can be replayed before all

15 songs are played.
Mathematics
1 answer:
blsea [12.9K]4 years ago
7 0

Answer:

Total songs = 15

Liked songs = 3

Un liked songs = 15-3=12

Find the probability that among the first two songs played

​(a) You like both of them.

Probability that among the first two songs played you like both of them = \frac{3}{15} \times \frac{2}{14} = 0.029

​(b) You like neither of them.

Probability that among the first two songs played you like neither of them = \frac{12}{15} \times \frac{11}{14} = 0.629

​(c) You like exactly one of them.

Probability that among the first two songs played you like exactly one of them = \frac{3}{15} \times \frac{12}{14}+ \frac{12}{15} \times \frac{3}{14}= 0.343

(d) Redo​ (a)-(c) if a song can be replayed before all

​(a) You like both of them. Would this be​ unusual?

Probability that among the first two songs played you like both of them = \frac{3}{15} \times \frac{3}{15} = 0.04

​(b) You like neither of them.

Probability that among the first two songs played you like neither of them = \frac{12}{15} \times \frac{12}{15} = 0.64

​(c) You like exactly one of them.

Probability that among the first two songs played you like exactly one of them = \frac{3}{15} \times \frac{12}{15}+ \frac{12}{15} \times \frac{3}{15}= 0.32

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