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zheka24 [161]
3 years ago
12

Find the perimeter of the figure.

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
8 0

Answer:

Well I’m not sure what you want but I’ll give you both,

The perimeter is 25 units

The area is 28.5 units ^2

Step-by-step explanation:

Well to find perimeter just count every unit which is what I did and got 25 units.

To find the area jsut split them into two shapes and find the area for both.

Triangle formula: bh/2

Rectangle: Lw

Well we have 3 for base and 3 for height.

3*3=9

9/2=4.5

4.5 is the triangle

We got 3 for width and 8 for length

3*8=24

24 is the rectangle

Add them up

24+4.5= 28.5

28.5 units

ruslelena [56]3 years ago
6 0

Answer:

28.5?

Step-by-step explanation:

I did this a while ago in 5th grade

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Convert the following sum into a product. cosx + cos3x + cos5x + cos7x
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Answer:

4\cos x\cos (4x)\cos (2x)

Step-by-step explanation:

Given: cosx + cos3x + cos5x + cos7x

To convert: the given sum into product

Solution:

Use formula: \cos A+\cos B=2\cos \left ( \frac{A+B}{2} \right )\cos \left ( \frac{A-B}{2} \right )

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos (2x)\cos (-x)+2\cos (6x)\cos (-x)\\=2\cos (2x)\cos (x)+2\cos (6x)\cos (x)\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]

cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]\\=2\cos x\left [2 \cos \left ( \frac{2x+6x}{2} \right )\cos \left ( \frac{2x-6x}{2} \right ) \right ]\\=2\cos x\left [ 2\cos (4x) \cos (-2x) \right ]\\=4\cos x\cos (4x)\cos (2x)

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Complete Question

The option to the blank space are shown on the first uploaded image

Answer:

Neal's decision is to <u>fail to reject </u> the <u>null hypothesis</u>   (p 0.066). There is <u>no sufficient </u> evidence to <u>prove</u> the claim that the average electricity consumption of <u>all  Ledee household </u>is <u>greater than</u> , <u>854.28 kWh</u>

Step-by-step explanation:

From the question we are told that

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   The sample size is  n =  65

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    The standard deviation is  \sigma  =  133.29 \  kWh

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Now from the given data we can see that

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Generally when this is the case , we fail to reject the null hypothesis

   So

Neal's decision is to <u>fail to reject </u> the <u>null hypothesis</u>   (p 0.066). There is <u>no sufficient </u> evidence to <u>prove</u> the claim that the average electricity consumption of <u>all  Ledee household </u>is <u>greater than</u> , <u>854.28 kWh</u>            

     

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