Answer
After 13.15 years the population of both towns will become equal.
Step-by-step explanation:
Population of the city Anville is given by using the compound interest formula
The formula of compound interest
A = p( 1+r/n)^n*t
using this we get
P1 = 16000 (1 +
) ^1*t
Population of the city of Brinker will be
P2 = 11000( 1 + 
) ^1*t
now to make equal population in both towns
P1=P2
16000 (1 +) ^1*t = 11000( 1 + ) ^1*t
t = 13.15 years
One A
y = e^x
dy/dx = e^x The f(x) = the differentiated function. Any value that e^x can have, the derivative has the same value. x is contained in all the reals.
One B
y = x*e^x
y' = e^x + xe^x Using the multiplication rule.
You want the slope and the value of the of y to be the same. The slope is y' of the tangent line
xe^x = e^x + xe^x
e^x = 0
This happens only when x is very "small" like x = - 4444444
y = e^x * ln(x) Using the multiplication rule again, we need the slope of the line with is y'
y1 = e^x
y1' = e^x
y2 = ln(x)
y2' = 1/x
y' = e^x*ln(x) + e^x/x So at x = 1 the slope of the line =
y' = e^1*ln(1) + e^1/1
y' = e*0+e = e
y = mx + b
y = ex + b
to find b we use y= e^x ln(x)
e^x ln(x) = e*x + b
e^1 ln(1) = e*1 + b
ln(1) = 0
0 = e + b
b = - e
line equation and answer.
y = e*x - e
Answer:
That equation is (2.5×2). The mean of the K is ×2
Answer:
10 weeks
Step-by-step explanation:
Let's set an equation for you and your brother.
You have $90 plus $18 for every week you save (x).
90+18x
And your brother has $120 plus $15 dollars per week that he saves (x)
120+15x
You want to have the sum of the money equal so combine the two concluded statements
90+18x=120+15x
Arrange them so that you have like terms on each side
90+18x-15x=12+15x-15x
90+3x=120
90-90+3x=120-90
3x=30
x=10
"x" is our number of weeks you and your brother save so the answer is 10 weeks
Just to be sure you can use our equation and plug 10 for every time you see x to make sure our answer is right.
1 electron has a mass of 9.1 X 10-31 kg. How many electrons n does it take to make 1 kg?
(1 e)/(9.1 X 10-31 kg) = n/(1 kg)
So, n = 1.10 X 1030 electrons
Each electron has a charge of 1.6 X 10-19 C, where C stands for Coulombs. So, the n electrons have a charge of q = ne = (1.10 X 1030 electrons) X (1.6 X 10-19 C/electron) = 1.76 X 1011 C.
