Justify Reasoning Determine whether 3x + 12 + x is equivalent to 4(3 + x). Use properties of operations to justify your answer.

What can be concluded about triangles RST and VTU?

LenKa [72]

Answer: It is A

Step-by-step explanation: Just did it on edg2020

6 0

3 years ago

Read 2 more answers

The owner of a moving company typically has his most experienced manager predict the total number of labor hours that will be re

ValentinkaMS [17]

Answer:

0.9538

Step-by-step explanation:

The computation of the proportion of variation in labor hours is explained by the number of cubic feet moved is shown below:

Here the R^2 coefficient of determination, would be determined and applied the same

R^2 = 1 - SSE ÷ SST

= 1 - 123.97 ÷ 2685.9

= 0.9538

3 0

3 years ago

Algebra 2 question need help thanks.

zysi [14]

B is the correct answer

4 0

3 years ago

What is the answer to:

velikii [3]

Weird way to write it but alright! (Sideways)

19pq^-2 x 5pq^6 = ?

These problems are pretty much single operations between each of the variables / constants.

So it's like this:

(19*5)(p*p)(q^-2*q^6) = ?

19*5 is 95.

For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.

p*p is p^2

For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:

-2 + 6 = 4
(The two is negative, because the power is negative 2)

So, q^4.

Our final answer is all of the combined.... like a so:

95p^2q^4

3 0

3 years ago

In a study on the time that

krok68 [10]

The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

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To solve this question, we need to find the confidence interval for the amount of time it takes the students to get the degree.

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

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The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 80 - 1 = 79

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95% confidence interval

Standard level of confidence, we have to find a value of T, which is found looking at the t table, with 79 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 1.9905.

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The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.9905\frac{2.2}{\sqrt{80}} = 0.5$

In which s is the standard deviation of the sample and n is the size of the sample.

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The lower end of the interval is the sample mean subtracted by M. So it is 4.8 - 0.3 = 4.3 years.

The upper end of the interval is the sample mean added to M. So it is 4.8 + 0.3 = 5.3 years.

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The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

A similar question is given at brainly.com/question/24278748

6 0

3 years ago