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yuradex [85]
3 years ago
5

What is the inverse of the relation​

Mathematics
1 answer:
Korolek [52]3 years ago
5 0
Y is not = to 1/4x-3
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Divide. −2 4/7 Enter your answer as a mixed number, in simplified form,
jarptica [38.1K]
I guess it's -24/7. So 24 divided by 7 is 3 remainder 3
The minus sign remains. So that will be -3 3/7
Hope I helped. Goodluck
5 0
2 years ago
I need the answer to this
spin [16.1K]

Answer:

parallel as if we place the ond the coordinate grkd they will form lines paral.el to each other(;

7 0
3 years ago
3/4 x 10 = ? <br> thank you!!!
lesantik [10]
3/4 *10 is 7.5. 0.75 * 10 = 7.5 
4 0
3 years ago
Read 2 more answers
The international cricket team is going to stadium to play the T20 cricket game. A coordinate grid is superimposed on a highway
marysya [2.9K]

Answer:

The coordinate of the rest stop is: (5,2.5)

The distance between the hotel and the stadium is 32 miles

Step-by-step explanation:

Given

(x_1,y_1) = (3,4) --- Team hotel

(x_2,y_2) = (7,1) --- Stadium

Solving (a): The coordinates of the rest stop

The rest stop is at half way;

So, the coordinate is:

(x,y) = \frac{1}{2}(x_1+x_2,y_1+y_2)

This gives:

(x,y) = \frac{1}{2}(3+7,4+1)

(x,y) = \frac{1}{2}(10,5)

Open bracket

(x,y) = (5,2.5)

Solving (b): Distance between the hotel and the stadium

We have:

(x_1,y_1) = (3,4) --- Team hotel

(x_2,y_2) = (7,1) --- Stadium

The distance (d) is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

So, we have:

d = \sqrt{(3 - 7)^2 + (4 - 1)^2}

d = \sqrt{(-4)^2 + 3^2}

d = \sqrt{16 + 9}

d = \sqrt{25}

d =5

From the question, we have:

1\ unit = 6.4\ miles

So:

d =5 * 6.4\ miles

d =32\ miles

3 0
2 years ago
GIVING BRAINLIESTTTTT
andreev551 [17]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

* Lets find the same steps in the constructions

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  "Place the compass on a point on the original line"

6 0
3 years ago
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