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Zolol [24]
3 years ago
13

Please help!! will give brainiest!!

Mathematics
2 answers:
lys-0071 [83]3 years ago
8 0

Answer:

espero te ayude es la opcion B

lisabon 2012 [21]3 years ago
7 0
Plan B because you spending less then plan A
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8. If the measure of one side of a square is increased by 2 centimeters and the measure of
GalinKa [24]

Answer:

  6 cm

Step-by-step explanation:

If the original side length is x, then the modified square has an area of ...

  A = LW

  32 = (x +2)(x -2) = x^2  -4

  36 = x^2 . . . . . . . . add 4

  6 = x . . . . . . . . . . take the square root

The original figure has a side length of 6 cm.

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<em>Check</em>

The modified figure is 8 cm by 4 cm = 32 cm^2.

8 0
2 years ago
If someone has a cube shaped box that measures 9 inches along each edge. Can they fit 1,000 1 square inch cubes inside the box
Stolb23 [73]

Answer:

The area of the box is equal to 9^3 = 729 in^3

729<1000  


Step-by-step explanation:

No since the volume of the box is less than the total volume of the cubes

4 0
3 years ago
Please help ILL MARK BRAINLIEST(17 points too)
jonny [76]

Answer:

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3 years ago
Please help! Due in 10 minutes, 7th grade math
RUDIKE [14]

Answer:

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Step-by-step explanation:

I predict these tingz

8 0
2 years ago
Read 2 more answers
You pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose 1 point.
Andreyy89

Answer:

a = 9\\b = 48\\c = -1

Step-by-step explanation:

We know that:

In a deck of 52 cards there are 4 aces.

Therefore the probability of obtaining an ace is:

P (x) = 4/52

The probability of not getting an ace is:

P ('x) = 1-4 / 52

P ('x) = 48/52

In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.

For a discrete random variable V, the expected value is defined as:

E(V) = VP(V)

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.

We have the following equation for the expected value:

E(V) = \frac{4}{52}(a) + \frac{b}{52}(c)

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52

Therefore, expected value for V, the number of points obtained in the game is:

E(V) = \frac{4}{52}(9) + \frac{48}{52}(-1)

So:

a = 9\\b = 48\\c = -1

3 0
3 years ago
Read 2 more answers
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