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FinnZ [79.3K]
3 years ago
9

3/4(x+21)=10 1/2 help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0

Answer:

-7

Step-by-step explanation:

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What is the equation in slope-intercept form of the line that passes through the points(-4,2) and (12,6)?
aleksandrvk [35]

Answer:

y=1/4x+3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-2)/(12-(-4))=4/(12+4)=4/16=1/4

y-y1=m(x-x1)

y-2=1/4(x-(-4))

y-2=1/4(x+4)

y=1/4x+4/4+2

y=1/4x+1+2

y=1/4x+3

3 0
3 years ago
Which represents the solution(s) of the system of equations, y = x2 – 2x – 15 and y = 8x – 40? Determine the solution set algebr
almond37 [142]

Answer:

(5, 0 )

Step-by-step explanation:

Given the 2 equations

y = x² - 2x - 15 → (1)

y = 8x - 40 → (2)

Substitute y = x² - 2x - 15 into (2)

x² - 2x - 15 = 8x - 40 ( subtract 8x - 40 from both sides )

x² - 10x + 25 = 0 ← in standard form

(x - 5)² = 0 ← in factored form, thus

x - 5 = 0 ⇒ x = 5

Substitute x = 5 into (2) for corresponding value of y

y = 8(5) - 40 = 40 - 40 = 0

Solution is (5, 0 )

3 0
3 years ago
M bisects QP, and QP = 27.4. Find QM.
KonstantinChe [14]

Answer:

13.7

Step-by-step explanation:

All you need to do is divide by 2, hope this helped!

4 0
3 years ago
Read 2 more answers
6. Solve for the variable: 11x - 22 = -11x - 22
pentagon [3]
11x-22=-11x-22
11x+11x=-22+22
22x=0
x=0/22
x=0
Then the answer is option B
8 0
3 years ago
Read 2 more answers
What is the area of the shaded region in the given circle in terms of pi and in simplest form?
BartSMP [9]

Answer:

Area of the shaded portion = (120π + 36√3)sq. m

Step-by-step explanation:

Area of the shaded region = Area of circle - Area of triangle

Given

radius of the circle = 12m

Area of the circle = πr²

Area of the circle  = π(12)²

Area of the circle  = 144π m²

Area of the sector = theta/360 * πr²

Area of the sector =  60/360 * 12²π

Area of the sector = 60/360 * 144π  = 24π

Area of the triangle = 1/2 bh

Area of the triangle = 1/2 (12cos30)(12)

Area of the triangle = 36√3

Area of the shaded portion = (144π - 24π + 36√3)sq. m

Area of the shaded portion = (120π + 36√3)sq. m

7 0
3 years ago
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