Answer:
b
Step-by-step explanation:
Answer:
The P-value for this test is P=0.2415.
Step-by-step explanation:
We have to perform an hypothesis testing on the mean of alla account balances.
The claim is that the mean of all account balances is significantly greater than $1,150.
Then, the null and alternative hypothesis are:

The sample size is n=20, with a sample mean is 110 and standard deviation is 125.
We can calculate the t-statistic as:

The degrees of freedom fot this test are:

For this one-tailed test and 19 degrees of freedom, the P-value is:

Answer:
22m+42 is the answer
Step-by-step explanation:
All you have to do is simplify and add the common factors.
Answer:y=-1/2
Step-by-step explanation:
125=(1/25)^(y-1)
5^3=(5^(-2))^(y-1)
5^3=5^(-2(y-1))
The same base eliminate each other we then have
3=-2(y-1)
3=-2y+2
Collect like terms
2y=2-3
2y=-1
Divide both sides by 2
2y/2=-1/2
y=-1/2