Veremos que el area del banderín es 930cm^2, entonces la opción correcta es A.
<h3>
¿Que area tiene el banderin?</h3>
Luego de una pequeña busqueda online, pude ver que el banderin es un triangulo isósceles con base de 31cm y altura de 60 cm.
Recordar que para un triangulo de base b y altura h, el area es:
A = b*h/2
Entonces el area del banderín va a ser:
A = (31cm)*(60cm)/2 = 930cm^2
Entonces la opción correcta es A.
Sí quieres aprender más sobre triangulos, puedes leer:
brainly.com/question/2217700
Answer: 37
Step-by-step explanation:
<u>Part 1)</u> A 20° sector in a circle has an area of 21.5π yd².
What is the area of the circle?
we know that
the area of a circle represent a sector of
degrees
so by proportion
therefore
<u>the answer part 1) is</u>
The area of the circle is 
<u>Part 2)</u> What is the area of a sector with a central angle of 3π/5 radians and a diameter of 21.2 cm?
we know that
the area of the circle is equal to

where
r is the radius of the circle
in this problem we have

<u>Find the area of the circle</u>



<u>Find the area of the sector</u>
we know that the area of the circle represent a sector of
radians
by proportion
therefore
<u>the answer part 2) is</u>
the area of the sector is

<h3>
Answer: Choice B</h3>
Use a rigid transformation to prove that angle NPO is congruent to angle NLM
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Explanation:
The AA stands for "angle angle". So we need two pairs of angles to prove the triangles to be similar. The first pair of angles is the vertical angles ONP and MNL, which are congruent. Any pair of vertical angles are always congruent.
The second pair of angles could either be
- angle NOP = angle NML
- angle NPO = angle NLM
so we have a choice on which to pick. The pairing angle NOP = angle NML is not listed in the answer choices, but angle NPO = angle NLM is listed as choice B.
Saying angle NLM = angle LMN is not useful because those two angles are part of the same triangle. The two angles must be in separate triangles to be able to tie the triangles together.
We would use a rigid transformation to have angle NPO move to angle NLM, or vice versa through the use of a rotation and a translation.
It is about 3,000. There is no #4 on your picture, so I just answered number one because that is all I saw.