2 years ago

What are the roots of the quadratic equation below 3x2+15x-5=0

Mathematics

1 answer:

fomenos2 years ago

8 0

Answer:

Step-by-step explanation:

$3x^2+15x-5=0\\a = 3\\b = 15\\c = -5\\ x = -b\±\frac{\sqrt{b^{2} -4ac} }{2a} \\x = -(15)\±\frac{\sqrt{15^{2} -4(3)(-5)} }{2(3)} \\x = -15 \±\frac{\sqrt{225+60} }{6} \\x = -15\±\frac{\sqrt{285} }{6} = A$

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