Answer:
<h2>
(f + g)(x)≥3 for all values of x</h2>
Step-by-step explanation:
Given the expressions f(x) = |x| + 9 and g(x) = –6, sine f(x) contains the absolute value of a variable x, this absolute value can be negative and positive. Therefore f(x) can be expressed in two forms as shown;
f(x) = x+9 and f(x) = -x+9
If f(x) = x+ 9 and g(x) = -6
(f + g)(x) = f(x)+ g(x)
(f + g)(x) = x+9+(-6)
(f + g)(x) = x+9-6
(f + g)(x) = x+3
Similarly, if f(x) = -x+ 9 and g(x) = -6
(f + g)(x) = f(x)+ g(x)
(f + g)(x) = -x+9+(-6)
(f + g)(x) = -x+9-6
(f + g)(x) = -x+3
(f + g)(x) = 3-x
In both expresson, we have bith x to be positive and negative, hence we can write the value of resulting x as an absolute value as shown;
(f + g)(x) = |x|+3
This shows that (f + g)(x)≥3 for all values of x
Answer:
5
Step-by-step explanation:
SQ= 10
SO is half way so divide by 2
Answer
1) true
2)false
3)false
4)true
5)true
Step-by-step explanation:
Answer:
P(at least one tail) = 7/8
Step-by-step explanation:
If you flip a coin, you have two outcomes- heads or tails. So let's find all the outcomes for flipping three coins.
H = heads. T = Tails
HHH P(what you want) = <u>number of times it happens</u>
HHT Total number of outcomes.
HTH
HTT P(at least one tail) = <u> 7 </u>
THH 8
THT
TTH
TTT
Answer: 120
Step-by-step explanation: 4(10)/1/2= 20
16-4=12
12(10)=120