so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.
we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.
![\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bcircumference%20of%20a%20circle%7D%7D%7BC%3Dd%5Cpi%20%7D~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20d%3D27%20%5Cend%7Bcases%7D%5Cimplies%20C%3D27%5Cpi%20%5Cimplies%20C%3D%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B84.78%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20rectangles%7D%7D%7B288%7D~~~~%2B~~~~%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20circle%7D%7D%7B84.78%7D~~~~%3D~~~~372.78)
Since you know that there was 96 total bracelets and Jackie made them for 8 days, if you are finding how much was made each day, it is division.
96/8=the number of bracelets made each day
Answer:7ft
Step-by-step explanation:
i got it right
Equations:
2x+105=-3x+130
<em>subtract</em><em> </em><em>2x</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em>
<em>105</em><em>=</em><em> </em><em>-5x</em><em>+</em><em>130</em>
<em>Subtract</em><em> </em><em>130</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em>
<em>-5x</em><em>=</em><em> </em><em>-25</em>
<em>isolate</em><em> </em><em>the</em><em> </em><em>variable</em>
<em>x</em><em>=</em><em>5</em><em> </em>
<u>Plug</u><u> </u><u>back</u><u> </u><u>in</u>
<u>2</u><u>(</u><u>5</u><u>)</u><u>+</u><u>105</u><u>=</u><u> </u><u>-3</u><u>(</u><u>5</u><u>)</u><u>+</u><u>130</u>
<u>115</u><u>=</u><u> </u><u> </u><u>115</u>
a, b, c - sides of a triangle
Therefore:
a + b > c
a + c > b
b + c > a
---------------------------------
We have a = AB, b = 140mi, c = 100mi.
(1) a + b > c
AB + 140 > 100 <em>subtract 140 from both sides</em>
AB > -40 → AB > 0
----------
(2) a + c > b
AB + 100 > 140 <em>subtract 100 from both sides</em>
AB > 40
-----------
(3) b + c > a → a < b + c
AB < 140 + 100
AB < 240
<h3>Answer: 40 < AB < 240</h3>
