Answer:
10/3/32
Step-by-step explanation:
:)))))))))))))))
Set up two equations:
1st: P (for Price family) + J (for Jenkins family) = 45 hours
2nd: 20P + 35J = 1200 liters
Rewrite the first equation as P = 45 – J
Replace P in the second equation:
20(45-J) + 35J = 1200
Simplify:
900 -20J + 35J = 1200
900 +15J = 1200
Subtract 900 from both sides:
15J = 300
Divide both sides by 15:
J = 300/15
J = 20
Jenkins used theirs for 20 hours
Price used theirs for 45-20 = 25 hours.
Answer:
-4^4(4^7), in that case, the answer would be (B) -4^11
Step-by-step explanation:
Hope this helps
Answer:
612 adults
361 students
Step-by-step explanation:
To solve this question, set two equations:
Let x be number of adults and y be number of students.
As there are in total 937 people, the equation would be the sum of both adults and children:

...... ( 1 )
As the total sale amount is $1109, the equation would be to add up the ticket fee:
...... ( 2 )
Put ( 1 ) into ( 2 ):





Put y into ( 1 ):
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
Therefore there are 612 adults and 361 students.
Answer:
see explanation
Step-by-step explanation:
Under a rotation about the origin of 90°
a point (x, y ) → (- y, x ), thus
A(2, 2 ) → A'(- 2, 2 )
B(2, 4 ) → B'(- 4, 2 )
C(4, 6 ) → C'(- 6, 4 )
D(6, 4 ) → D'(- 4, 6 )
E(6, 2 ) → E'(- 2, 6 )