The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
Answer:
slope = - 
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 2x + 5 is in this form with slope m = 2
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= -
For part a,
y < x
y > -2x
Point B: (3,1) plugin x=3, y=1 y < x 1 < 3
which is true, so point B satisfies the first inequalityYou can graph the inequality y > 2x+5 and see which schools are in the shaded region
Answer:
12
Step-by-step explanation:
The formula for the tangent of an angle is the length of the opposite side divided by the length of the adjacent side. Therefore, the tangent of angle x is 420/2000=0.21. Taking the arctangent of that to get the angle, you get about 12 degrees. Hope this helps!
Answer:
Step-by-step explanation:
