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Klio2033 [76]
3 years ago
7

Buses to exeter leave a bus station every 20 minutrs busses to plymouth leave the bus satation every 16 minutes a bus to eveter

and a bus ro plymouth both leave the bus at 8 am when will busses to exeter and a bis to plymouth next leave the bus sata
Mathematics
1 answer:
frez [133]3 years ago
8 0

Answer:

  9:20 am

Step-by-step explanation:

The cycles will coincide again at the least common multiple of the cycle times.

  20 min = 4 × 5 min

  16 min = 4 × 4 min

The least common multiple of these times is 4 × 4 × 5 min = 80 min. 80 minutes after 8 am is 9:20 am.

The two buses will next leave at once at 9:20 am.

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Answer: .97 cents

Step-by-step explanation:

$3.88 ÷ 4 bottles of Gatorade = .97 cents each

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Solve for x on both problems! please help! will give brainiest
Fudgin [204]

Answer: # 15 is x=-12 and #16 is x=24

Step-by-step explanation:

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Which equation represents a line that passes through (2, –0.5) and has a slope of 3?
Kitty [74]
A slope of 3 means the gradient is 3 so we get y=3x+c as derived from the linear formula. we then sub in x=2 and y=-0.5. this gives us c=-6.5.

The equation would be y=3x-6.5

I think this is right.
4 0
3 years ago
Read 2 more answers
What is equivalent to ln(e^3)
malfutka [58]

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3

Step-by-step explanation:

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(This is the also same as e^(ln3))

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3 years ago
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Math again yay!...Ew math
Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

f(x)=x^2

New function:

g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2

<u>Transformations</u>:

For a > 0

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}

\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}

If the parent function is <u>shifted ¹/₄ unit up</u>:

\implies g(x)=x^2+\dfrac{1}{4}

If the parent function is <u>shifted ¹/₄ unit down</u>:

\implies g(x)=x^2-\dfrac{1}{4}

If the parent function is <u>compressed vertically</u> by a factor of ¹/₄:

\implies g(x)=\dfrac{1}{4}x^2

If the parent function is <u>stretched horizontally</u> by a factor of ¹/₂:

\implies g(x)=\left(\dfrac{1}{2}x\right)^2

Therefore, a vertical compression and a horizontal stretch mean that the graph of g(x) is wider.

4 0
2 years ago
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