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3 years ago

9

Describe your understanding of finding percents of a whole.

1 answer:

zhuklara [117]3 years ago

8 0

Step-by-step explanation: Write down the whole number amount, for example: 500. Calculate the equation. The result is the decimal equivalent of the percentage. Multiply the decimal equivalent of the percentage by 100; or move the number's decimal point over two places to the right.

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What is the LCD for 11/21 and 31/45

Leokris [45]

There is none except for eleven and that is it

8 0

3 years ago

(t-2)(t+1)(t+1) what is this when foiled out

mario62 [17]

(t-2)(t+1)(t+1)
t^2+t-2t-2(t+1)
t^2-t-2(t+1)
t^3-t^2-2t+t^2-t-2
t^3+-3t-2

3 0

3 years ago

Read 2 more answers

A hypothesis test is conducted at the .05 level of significance to test whether or not the population correlation is zero. If th

finlep [7]

Answer:

Th computed value of the test statistic is 3.597

Step-by-step explanation:

The null and the alternative hypothesis is as follows:

Null Hypothesis:

$\mathbf{H_o:}$ the population correlation coefficient is equal to zero

$\mathbf{H_a:}$ the population correlation coefficient is not equal to zero

The test statistics for Pearson correlation coefficient is thus computed as :

$t =\dfrac{r \sqrt{(n-2)}} { \sqrt{(1-(r)^2)} }$

where;

r = correlation coefficient = 0.60

n = sample size = 25

So;

$t =\dfrac{0.60 \sqrt{(25-2)}} { \sqrt{(1-(0.60)^2)} }$

$t =\dfrac{0.60 \sqrt{(23)}} { \sqrt{(1-0.36} }$

$t =\dfrac{0.60 *4.796} {0.8}$

t = 3.597

Comparing to a critical value of t (23 degrees of freedom two-tailed value) = 2.069

Decision Rule:

Since computed value of t is greater than the critical value of t; We reject the null hypothesis and accept the alternative hypothesis.

Conclusion:

We conclude that the population correlation coefficient significantly differs from 0 at 5% (0.05) level of significance.

6 0

3 years ago

60points if you answer

Anton [14]

-4 > -5, -4 is > or equal to 5

7 0

2 years ago

Read 2 more answers

85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C

Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = $\frac{85.87}{0.4360}$

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C Answer

7 0

2 years ago