Considering the expression of a line, the slope of the line passing through (6,-2) (1, 8) is -2.
<h3>Linear equation o line</h3>
A linear equation o line can be expressed in the form y = mx + b
where
- x and y are coordinates of a point.
- m is the slope.
- b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.
Knowing two points (x1, y1) and (x2, y2) of a line, the slope m can be calculated using the following expression:
m= (y2 -y1)÷ (x2 -x1)
Substituting the value of the slope m and the value of one of the points in the expression of a linear equation, the value of the ordinate to the origin b can be obtained.
<h3>Slope of the line in this case</h3>
Being (x1,y1)= (6, -2) and (x2,y2)= (1, 8), the slope m can be calculated as:
m= (8 - (-2))÷ (1 - 6)
m= 10÷ (-5)
<u><em>m= -2</em></u>
Finally, the slope of the line passing through (6,-2) (1, 8) is -2.
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